(10a/9)/(9a^3/8)
(10a/9)*(8/(9a^3))
(80a)/(81a^3)
(80/81)a^(1 - 3)
(80/81)a^(-2)
ANS : 80/(81a^2)
2006-06-21 09:41:00
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answer #1
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answered by Sherman81 6
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To divide fractions you need to multiply by the reciprocal of the divisor. In other words:
10a / 9 * 8 / 9a^3 = 80a / 81a^3 = 80 / 81a^2
2006-06-21 16:53:13
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answer #2
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answered by jimbob 6
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10a/9 / 9a^3/8 = 10a*8/9*9a^3 = 80/81a^2
2006-06-21 12:51:30
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answer #3
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answered by ag_iitkgp 7
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80/(81 a^2)
Eighty divided by eitghty-one times a squared.
2006-06-21 12:58:55
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answer #4
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answered by the_mad_scientist 1
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80 / 81 a^2
2006-06-21 12:50:50
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answer #5
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answered by csucdartgirl 7
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i have a ques. 4 u if u r in 9th grade pick me as best answer cuz i need 2 know if i should drop out... i luv algebra and i could not figure that 1 out!
2006-06-21 13:05:44
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answer #6
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answered by chix 1
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( (10/9) a ) / ( 9 a^(3/8) ) =
( (10/9) a^(8/8) ) / ( 9 a^(3/8) ) =
( (10/9) a^(5/8) ) / ( 9 ) =
( (10/9) a^(5/8) ) x 9 / ( 9 ) x 9 =
( 10 a^(5/8) ) / 81
2006-06-21 12:53:07
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answer #7
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answered by Anonymous
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10a^5/8 / 81
practice your rearrangements and this will get easier.
2006-06-21 12:52:11
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answer #8
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answered by shiara_blade 6
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I don't answer math questions any more since the askers rarely select a best answer. They only want to cheat on their homework.
2006-06-21 12:52:11
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answer #9
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answered by Anonymous
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=8.889a^(-2)
2006-06-21 12:54:18
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answer #10
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answered by m_omiiid 1
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