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11 answers

loses

2006-06-21 02:09:42 · answer #1 · answered by TheHza 4 · 0 0

Fewer than 4 would mean it would LOSE electrons normally to become balanced, since it would be easier to get rid of 1-3 electrons then to grab 5 or more.

2006-06-21 02:14:33 · answer #2 · answered by Nate 3 · 0 0

If i am going to save in recommendations maximum recommendations-blowing, there are 8 valence electrons contained in the outter shell. less than is a quote from Wikipidea: The valence shell is the outermost shell of an atom in its uncombined state, which includes the electrons maximum in all likelihood to account for the nature of any reactions in regards to the atom and of the bonding interactions it has with different atoms. The outermost shell of an ion isn't many times termed valence shell. Electrons contained in the valence shell are referred to as valence electrons. The actual chemist Gilbert Lewis became to blame for far of the early progression of the perception of the participation of valence shell electrons in chemical bonding. Linus Pauling later generalized and prolonged the perception at the same time as utilising insights from quantum mechanics. In a noble gasoline, an atom has a tendency to have 8 electrons in its outer shell (except helium, it really is in undemanding words waiting to fill its shell with 2 electrons). This serves because the variety for the octet rule it really is regularly proper to significant team factors of the second one and 0.33 sessions. in words of atomic orbitals, the electrons contained in the valence shell are dispensed 2 contained in the only s orbital and 2 each and each contained in the three p orbitals. For coordination complexes containing transition metals, the valence shell includes electrons in those s and p orbitals, besides as as a lot as ten extra electrons, dispensed as 2 into each and each of 5 d orbitals, to make a finished of 18 electrons in an finished valence shell for any such compound. that is known because the eighteen electron rule. each and each shell (n=a million, 2, 3, 4) can carry 2, 8, 18, or 32 electrons (2n2 electrons). that is taken into consideration needed to observe that the variety of valence electrons isn't unavoidably equivalent to the completed variety of electrons in a given electron shell. for instance, because the three-D subshell has a larger potential than the 4s subshell, the three-D electrons are seen to be an element of the 4th valence shell. So, at the same time as the third electron shell can contain a finished of 18 electrons (2 contained in the 3s orbital, 6 contained in the 3p orbitals, and 10 contained in the three-D orbitals), the third valence shell includes in undemanding words 8 electrons because the three-D electrons are many times no longer component of the third valence shell.

2016-11-15 01:41:07 · answer #3 · answered by poul 4 · 0 0

ok it can go either way depending on which element you're talking about. transition metals are likely to lose electrons, but those in the p orbital (right of periodic table) will gain electron to become balanced mostly through bonding.

2006-06-21 05:49:51 · answer #4 · answered by shiara_blade 6 · 0 0

if atom hav fewer than 4 electron it can easily loses it electron to get most stable electronic configuraton ,hence its outer most shell is fully filled ........and become stable

2006-06-21 02:48:04 · answer #5 · answered by Atul 1 · 0 0

To complete this sentence properly we put the word (loses)

2006-06-21 05:39:23 · answer #6 · answered by RASHA A 1 · 0 0

They lose electrons. Go to

http://www.howe.k12.ok.us/~jimaskew/cbond.htm

2006-06-21 02:11:25 · answer #7 · answered by I Am 2 · 0 0

my chemistry teacher didn't teach me anything but stuff about football.

2006-06-21 05:05:46 · answer #8 · answered by simcityat_thecrazylife 1 · 0 0

attracts to fill its valence shell

2006-06-21 02:11:22 · answer #9 · answered by Aaron G 2 · 0 0

attracts

2006-06-21 02:09:33 · answer #10 · answered by Anonymous · 0 0

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