How to solve this maths problems..????

Question

Adam has 3times as many stamps as Xinlong and an additional 6 stamps,Cindy has 1/6 of What adam has and additonal 2 stamps,Cindy has 4 stamps fewer than xin long.
A)how many stamps do they have altogether?
B)How many stamps must adam give xinlong so that they will have the same number of stamps?

Please help me!!!!! thanksss!!

Nic, I want an answers, not "Are you are Mathematician..?"

Answer 1

The total is 72. (Adam has 48, Cindy has 10 and Xinlong has 14)

Adam needs to give 10 stamps to Xinlong (and 14 to Cindy) to even the set (24 each)

Answer 2

You have three equations with three variables.

Let Adam =A, Xinlong = X, Cindy = C.
Adam has 3 times... ... and additional 6...

Equation 1) A=3X+6

Cindy has 1/6... and additional 2...

Equation 2) C=1/6A+2 or 1/6A=C-2 or A=6C-12

Cindy has 4 fewer than xinlong.

Equation 3) C=X-4

If you substitut the value of C in equation 3 into equation 2, you can rewrite equation 2 as:

A=6(X-4)-12 or A=6X-24-12 or A=6X-36

Since Equation 1 and Equation 2 are both equal to A, you can substitute the value of a in equation 2 into equation 1 as:

6X-36=3X+6

Subtract 3x from both sides of the equation, you'll get:
3X-36=6

Add 36 to both sides, you get:

3X=42

Divide both sides by three, and you find:
X=14

Xinlong has 14 Stamps.

Substitute 14 for x in equation 3 and you'll get:
C=X-4 or C=10.

Cindy has 10 Stamps.

Looking at Equation 1,
A=3X+6 or A=(3*14)+6 or A=48

Adam has 48 Stamps

Add A, C and X together, you will see that
48+14+10=72

a) They have 72 Stamps all together.

To have the same amount of stamps, Adam and Xinlong must put their stamps together and divide by two.

So, (48+14)/2 = 62/2 = 31. Since adam has 48, he must surrender 48-31=17 stamps.

b) Adam will give Xinlong 17 stamps.

Answer 3

Let the no. of stamps with xinlong = m

Hence, no. of stamps with adam = 3m+6

And, no of stamps with cindy = (3m+6)/6 + 2

Its given that Cindy has 4 stamps fewer than xin long, this means that if we subtract the no of stamps with cindy, we should get 4.

Hence,
m - [(3m+6)/6 + 2] = 4

m - [(3m+6+12)/6] = 4 (solving the term in the round bracket)

6m - 3m - 18 = 24 (solving further and cross multiplying)

3m = 42

m = 14
Therefore, xinlong has 14 stamps i.e m = 14
adam will have 3(14) + 6 = 48 stamps
and cindy will have 48/6 + 2 = 10 stamps

A) They have 14+48+10 = 72 stamps altogether

B) Adam must give (48-14)/2 = 17 stamps to xinlong so that the number of stamps with them is equal i.e 17.

Answer 4

Let : a = Adam, x = Xinlong, c = Cindy
Then : a = 3x + 6
c = 1/6a + 2
x = c + 4

x to a :
a = 3(c + 4) + 6
= 3c + 12 + 6
= 3c + 18

a to c :
c = 1/6a + 2
c = 1/6(3c + 18) + 2
c = 1/2c + 3 +2
c = 1/2c + 5
1/2c = 5
c = 10

c=10 ; x=14 ; a=48

altogether = c + x + a
= 10 +14 + 48
= 72

As : c + a = 58,
half will be = 29

a - n = 29
48 - n = 29
n = 17

Adam must give Xinlong 17 stamps to have equal amount...

Answer 5

First, assign letters to represent each quantity of stamps. Let's say Adam has a stamps, Xinlong has x stamps, Cindy has c stamps.

Now, write equations to express the given information algebraically.
a=3x+6
c=a/6+2
c=x-4

One way to solve this is by substitution to eliminate one of the variables and reduce to 2 equations and 2 unknowns.
c=(3x+6)/6+2=x/2+1+2=x/2+3
c=x-4

Now substitute again, i.e. set the two equations for c equal to one another, and solve for x.
x/2+3=x-4
x/2+7=x
7=x/2
14=x

Then go back and plug 18 in for x to find a and c.
a=3*14+6=48
c=14-4=10

A) The answer is a+x+c=48+14+10=72

B) You need to name another variable for the number of stamps that Adam will need to give Xinlong. Let's call it n.

The number of stamps that Adam has will be 48-n and the number of stamps that Xinlong has will be 14+n, so
48-n=14+n
48=14+2n
34=2n
17=n

And that's the answer, Adam will need to give Xinlong 17 stamps.


Awwww someone else answered while I was typing... Oh well, at least now you get 2 good answers.

People like to give bad or short answers because you get points for answering no matter how useless your answer is.

Answer 6

i'm not a mathematician...

Answer 7

not that smart