What is the third term in the expansion of (x+3)^5?

Answer 1

you need to know the Binomial Therem
the third term is going to be
5c2*x^3*3^2
=10*x^3*9
=90x^3

Answer 2

The binomial boom is one merchandise in a series of pleasing and exciting products. the first exciting merchandise in this sequence is the monomial boom. The coefficients of the time period of increasing powers n=0,a million,2,3,4,... of a monomial variety a in simple terms classy merchandise referred to as Pascal's column. that is actual remembered (or reconstructed) and appears like a million a million a million a million a million ... the subsequent is the binomial boom. The coefficients of the words in increasing powers n=0,a million,2,3,4,... of a binomial variety an merchandise referred to as Pascal's triangle. It follows from Pascal's column through summing the column to the left above. It appears like a million a million a million a million 2 a million a million 3 3 a million a million 4 6 4 a million ... the first column in Pascal's triangle is in simple terms Pascal's column. the second one column is in simple terms the organic numbers a million, a million+a million, a million+a million+a million, a million+a million+a million+a million, .... The 0.33 column is the triangular numbers a million, a million+2, a million+2+3, .... The fourth column is the tetrahedral numbers a million, a million+4, .... etc. the subsequent merchandise is the trinomial boom. The coefficients variety Pascal's tetrahedron, which follows from his triangle analogously to how his triangle follows from his column. Pascal's tetrahedron is a three-dimensional affiliation of the coefficients of the words of increasing powers of a trinomial. Then comes Pascal's pentope, a 4-dimensional merchandise, etc with out end. each and each Pascal's merchandise is touching on to the former merchandise very in simple terms. All that is too pleasing to actual describe in words.

Answer 3

(x + 3)^5

(x + 3)(x + 3)(x + 3)(x + 3)(x + 3)

(x^2 + 6x + 9)(x^2 + 6x + 9)(x + 3)

(x^4 + 6x^3 + 9x^2 + 6x^3 + 36x^2 + 54x + 9x^2 + 54x + 81)(x + 3)

(x^4 + 12x^3 + 54x^2 + 108x + 81)(x + 3)

x^5 + 3x^4 + 12x^4 + 36x^3 + 54x^3 + 162x^2 + 108x^2 + 324x + 81x + 243

x^5 + 15x^4 + 90x^3 + 270x^2 + 405x + 243

ANS : 90x^3

Answer 4

(x+3)^5 = x^5 + 15x^4 + 90x^3 + 270x^4 + 245x^5 + 243

So the answer for you is 90x^3

Thanks...

Answer 5

90x^3 or 5c2(x^3)(27)

Answer 6

use binomial expansio

Answer 7

I have no Idea wat you talking about !