4x^2+5(x-2)(x-7) Please explain the answer. Thank u
2006-06-20 17:57:31 · 8 answers · asked by Letrise 5 in Science & Mathematics ➔ Mathematics
distribute and then combine like terms
2006-06-20 18:01:37 · answer #1 · answered by yoyobangbangjiggyjiggywithit 2 · 0⤊ 0⤋
First remember to multiply all the terms in each set of parentheses(). Then combine like terms and add/subtract. An important thing to remember is the order of multiplication does not matter. However, because of the parentheses, each set is independent. Due to the 5 here, you'll need to multiply 5 by the first or the 2nd set (either way works). Another way of looking at the equation is this:
4x^2 + (5 *(x-2) * (x-7))
4x^2 + (5x -10)(x-7)
4x^2 + 5x^2 - 35x -10x + 70
combine like terms:
9x^2 - 45x + 70
To prove the other way:
4x^2 + (5x-35)(x-2)
4x^2 + 5x^2 -10x -35x + 70
combine like terms:
9x^2 -45x + 70
Hope that helps.
2006-06-21 01:24:33 · answer #2 · answered by jeffrey_meyer2000 2 · 0⤊ 0⤋
You don't have an equation there, so all that you can do is change it into a polynomial expressed in powers of x, by multiplying out and collecting like terms and then factoring if possible.
Start: (x-2)(x-7) = x^2 -9x +14, times 5 =
5x^2-45x+70
So your polynomial is:
4x^2+5x^2-45x+70 = 9x^2 -45x +70
Now if you can simplify it by factoring then do so. In this case, it's okay as is.
2006-06-21 01:15:17 · answer #3 · answered by Jimbo 5 · 0⤊ 0⤋
OK, so assuming this equation equals 0 then combine the terms on the right using the FOIL method. You should get an ax^2 term and a bx term combine the ax^2's together and you should have a quadratic equation, ax^2+bx+c=0, while the signs might be different you can solve this either by factoring the numbers out again and solving for each or you can use the quadratic equation. Hope this helps good luck
2006-06-21 01:15:13 · answer #4 · answered by Chemist 2 · 0⤊ 0⤋
4x^2 + 5(x-2)(x-7) Original Problem
4x^2 + 5(x^2-2x-7x+14) unfactor
4x^2 + 5x^2 - 9x + 14 Combine like terms (-2x-7x)
9x^2 - 9x = -14 Combine like terms (4x^2 +5x^2)
9x^2-9x-18= -14-18 Complete the square
(3x-6) (3x+3)=-32 Factor
Here you split the problem (almost done)
3x-6=-32
3x=26
x = -26/3 is one zero
3x + 3= 32
3x=29
x= 29/3 is the other zero
So x= +29/3 & x= -26/3
check it on your graphing calculator
2006-06-21 01:23:06 · answer #5 · answered by the_texas_hammer 3 · 0⤊ 0⤋
4x^2 + 5(x - 2)(x - 7)
4x^2 + 5(x^2 - 7x - 2x + 14)
4x^2 + 5(x^2 - 9x + 14)
4x^2 + 5x^2 - 45x + 70
9x^2 - 45x + 70
2006-06-21 01:25:49 · answer #6 · answered by Sherman81 6 · 0⤊ 0⤋
What do you want?
To solve the equation or to factorize it?
or to draw the graph of the parabola?
Let be consider it as an equation.
4x^2+5(x^2-7x-2x+14)=0
4x^2+5x^2-45x+70=0
9x^2-45x+70=0
use quadratic formula
delta is negative
So, no real roots.
Solution set is empty.
2006-06-21 01:09:47 · answer #7 · answered by iyiogrenci 6 · 0⤊ 0⤋
Yes i can help u.Bye
2006-06-21 04:27:42 · answer #8 · answered by v_aravind_kulasekhar 1 · 0⤊ 0⤋