solve for X need help! (x+5)^2+1=37?

Question

square root 2x-1=7

square root x+2=6

Answer 1

(x + 5)^2 + 1 = 37
(x + 5)^2 = 37 - 1 = 36
x + 5 = +- 6
Here you have two solutions:
x = -11
and
x = 1

Answer 2

The first one is X=1, because 5+1=6 and 6^2 is 36, add 1 to that and you get 37.
The second one is X=25 because 25 x 2 is 50 and minus 1 is 49, and the sq. root of 49 is 7.
The third one is X=34 because 34 +2 is 36, and the sq. root of 36 is 6.

Good luck, hope i helped!

Answer 3

#29 utilising the time period product signifies that 2 factors are being more advantageous that effect in an answer. the answer is termed a product. celebration: 2 (a element) x (cases) 4 (a element) equals 8 (it really is the product). 8 more effective than the made from 6 and n would study: upload 8 to the answer of 6 more advantageous through n 6 cases n is written as 6n including 8 would look as if: 6n+8 or 8+6n #30 some thing is lacking with the intention to substitute values, you need to have an expression or formula to plug the values into. once you locate the equation in simple terms substitute the enormous choice 2 for the "x" . positioned 5 in decision to the letter y, and positioned the enormous choice a million the position you locate the letter z. Then do the mathematics.

Answer 4

> x = 1 or -11
> x = 25
> x = 34

Answer 5

x equals 1 for the first
equals 25
equals 34 in the third if i understand what you are asking correctly you should use parentheses to show what you mean

Answer 6

(x+5)^2 = 37-1
(x+5) = SQRT(37-1)
x = SQRT(37-1) -5
x= 1

SQRT(2x) -1 +1 = 7 +1
SQRT(2x) = 8
[SQRT(2x)]^2 = 8 ^2
2x = 16
2x/2 = 16/2
x = 8