probabilty that at least 10 sheep will die from the disease.
Final answer = [0.12]
2006-06-20 14:42:03 · 3 answers · asked by $ MATH THUGZ 4 LYFE $ 2 in Science & Mathematics ➔ Mathematics
To calculate the probability that at least 10 will die, you need to calculate the probability that 10, 11, 12, ... 20 will die:
The probability that n sheep will die is
P(n) = (20Cn) * (0.35)^n*(0.65)^(20-n)
P(10) = 0.06861397200
P(11) = 0.03358725903
P(12) = 0.01356408538
P(13) = 0.004494608173
P(14) = 0.001210086815
P(15) = 0.0002606340833
P(16) = 0.00004385669671
P(17) = 0.000005556504561
P(18) = 0.0000004986606658
P(19) = 0.00000002826416730
P(20) = 0.0000000007609583502
sum = 0.1217805865
2006-06-20 15:18:10 · answer #1 · answered by fatal_flaw_death 3 · 0⤊ 0⤋
1 - binomcdf (20, 0.35, 9) = 0.12
2006-06-20 15:01:19 · answer #2 · answered by snowdrop_crystal 2 · 0⤊ 0⤋
2 * (20 C 10 )* [(0.35)^10] *[ (0.65)^10 ]
2006-06-20 14:47:09 · answer #3 · answered by sunil 3 · 0⤊ 0⤋