You are lying 120 ft away from a tree that is 50 feet tall. You look up at the top of the tree.?

Question

Approximatley how far is your hear from the top of the tree in a straight line?
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Please explain how u got ur answer

Answer 1

Use the Pythagorean theorem.
50^2+120^2=x^2
x^2=2,500+14,400
x^2=16,900
x=130

Answer 2

There are particular varieties of proper triangles with particular ratios to at least one yet another. Your tree situation is a common 5-12-13 situation. have you ever realized about 3-4-5 triangles? you understand how 3^2+4^2=5^2? properly, 5^2+12^2=13^2. So because you've one aspect being 50 (the top of the tree), one being one hundred twenty (how far you're), then the gap you seem (the hypotenuse) could be one hundred thirty. 50-one hundred twenty-one hundred thirty will be a similar as 5-12-13 (similar ratio).

Answer 3

Tree Height Measurement by Michael Kuhns, Extension Forestry Specialist

You can measure heights of very tall objects such as trees by projecting a right triangle (one that includes a 90 degree angle) using your arm, a stick, and your line-of sight.


Procedure

1. Get a stick that is equal in length to the distance from your eye (cheekbone) to your fingers when your arm is fully extended in front of your face. Break off part of the stick or mark it at the correct length if you don't find one that is exactly right.

2. Grasp the stick by the tips of the thumb and index finger and hold it out in front of you with your arm fully extended. The stick must be held vertical.

3. Walk toward or away from the tree until the tip of the stick is visually lined up with the top of the tree and the bottom of the stick is lined up with the bottom of the tree. Your line of sight to the tree base should be as close as possible to horizontal. In sighting to the top and bottom of the stick rotate your eye rather than your head.

4. The distance from your eye to the base of the tree is equal to the height of the tree. Measure this distance with a measuring tape. If no long-distance measuring device is available, calibrate your step (the walking distance between your two feet--walk normal, don't stretch) or pace (walking distance for two steps) over a known distance (say 50 feet). Then measure the distance A-D in paces or steps and convert to feet, meters, etc.

Answer 4

Easy.

Make a right triangle with one leg 50, and the other 120

do the pythagorean theorem

50² + 120² = c².

2500 + 14400 = c²

16900 = c²

put a radical sign (√) over c² and 16900

and c = 130.

your head is 130 feet away from the tree.

Answer 5

Pythagorean Theorem: a^2 + b^2 = c^2 where c is the hypotenuse.
50^2 + 120^2 = 16900
130

Answer 6

pretty much the question is asking youtto use the pythagorean theorem, which is a2+b2=c2, and theshape of u and the tree forms a triangle. so what u do is u swuare 50 and120 and add them together to get16900 ft, which is how long the straight line was.

Answer 7

a^2 + b^2 = c^2
50^2 + 120^2 = c^2
2500 + 14400 = c^2
16900 = c^2
c = 130

Your head is 130 ft from the top of the tree.

Answer 8

130 ft. If I did the math right...forgive me if I didnt.. But i did the a2+b2=c2 Pathagoean. A=50 B=120 C=x
50 squared is 2500, 120 squared is 14400 add those two together and you get 16900 square root that and you get 130 and that i believe is your X.

Answer 9

Use the pythagorean theorem, where the height and distance are the "legs" and the unknown as the "hypotenuse" of the "right triangle".
The theorem is:
(legA)² + (legB)² = (hyp)²

Solving for hyp,
hyp = sqrt(legA² + legB²)
hyp = sqrt(50² + 120²)
hyp = sqrt(2500 + 14400)
hyp = sqrt(16900)
= 130

the answer, 130 ft.

^_^

Answer 10

a^2 + b^2 = c^2
You are looking for c. It doesn't matter which one is a and which one is b.
(120)^2 + (50)^2 = c^2
14400 + 2500 = c^2
16900 = c^2
sqrt(16900) = sqrt(c^2)
130 = c
Answer: 130 feet