i have to make graphs for these equations....can someone help me.....?

Question

the equations are i have to graph, but i know i have to solve them first right........???please help.......:
y=2x,
y=x^2-4x
y=-x+1
y=-x^2+3x
=x^2+1
Y=x+1
y=2x^2

Answer 1

You have two ways to do it...
One... if you have to do it on a graph paper...
then.. put some values of x and solve for y and make a table... and then plot those points on graph

Otherwise.. use graph plotting softwares.. like gnuplot (which is a free software).. define function as f(x)=2x (f(x) is equivalent to y here) and say plot f(x).. it will plot you the function.

Answer 2

you have to set up the equation as follows y x

2
3
4

You can make x any value that you want. then you just solve for y. So if x=2 then you would take (in the case of your first problem) 2 times x (which is 2) so you would get four. so y=4.

For the third one, say x=5. You would take -5=1=-4.

I think that should make it a little more understandable for you. If not im sorry.
so if x

Answer 3

well, you did good solving for y.
**Now the basic graph is x=y and it is just a diagonal line going through the origin (up one, right one *point*, up one, right one *point*,ect). you also have y=-x which is the same thing, except the line goes the other way (up one, left one, up one left one) **anything y=x+2 or 3 or 5 or whatever, you just take the same line, and move it up 2 or 3 or 5 or whatever number it is (ex. if it is y=x+12, you take the line of y=x and movie it up to 12.). if it is minus 2 or 3 or 5, you move the graph down.
**if your x has a number in front of it, your slope has changed (how slanted the diagonal line is). now one of your problems is y=2X. so you will start at 0,0 and go up 2, over (right) one. up two, over one. ect. then (from 0,0) go down two, left one, ect.
**now, the ones where x is squared are called parabolas. they are all in the form y = ax2 + bx + c. one of your problems is y=x^2+3x. so your a is 1 (because it is just x), your b is 3 and your c is zero. so, the way to solve them is make a chart with three columns. one with your x values (-1,0,1,2,3,4,5), the middle column with your equasion (y=x^2+3X) and the third with your y values (which you dont know yet.) You plug in your x values into your equasion-example, you start with -1. so in your equason, whereever there is an x, put a -1 there instead. so your equasion will say y=(-1)^2+3(-1). then solve for y. -1^2 is 1, and 3 times -1 is -3. so your first ordered pair is 1,-3. repeat with every x value, then draw the points, and connect. it should make a curved shape. good luck!

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Answer 4

Just give yourself an easy set of numbers for X and then plug them into the equation you want to graph.

Do this one at a time to get each graph drawn out.

They can be a pain at first, but you will get the hang of them soon enough.

Answer 5

These are all indeterminate equations. You need to plot a line.

y = 2x is a diagonal line passing through (0,0) and with a slope of 2.
y = x^2+4x is a parabola also passing through (0,0), I'm not sure in which direction...
y = -x+1 is a diagonal line passing through (1,0) and (0,-1), with a slope of 1.
I'm not sure about most of the rest...

Answer 6

no need to solve - you just plot them.

write several values of X in one column (e.g. -2, -1, 0, 1, 2 ), then compute Y for each X and write it in the second column, then plot them on the graph

You can do it in Excel if you have it (generate numbers, then go to menu Insert/Graph)

Answer 7

put a number in for the x and then see what the y is equal to use a couple of different numbers for x to get a bunch of points. Then plot the points.

Answer 8

http://www.calculator.com/calcs/GCalc.html

Here are how to type in the problems

2x
x^2 - 4x
-x + 1
-(x^2) + 3x
x^2 + 1
x + 1
2x^2

You notice i typed -x^2 like -(x^2), its because the site i gave you will take it like this (-x)^2 instead of -(x^2). Also make sure to leave out the y = part, because as long as you have it in y = form, you don't need it.