What is the total amount of heat energy, in joules, absorbed by 25 grams of water when the temperature of the water increases from 24 degrees celsius to 36 degrees celsius?
2006-06-20 08:38:13 · 5 answers · asked by E.F. 2 in Science & Mathematics ➔ Chemistry
Q (heat energy) = m(mass in gram)*c(specific heat in J/gm/K)*t (change in temp)
Q = 25 * 1 * (36-24)
Q = 300 J
2006-06-20 08:50:06 · answer #1 · answered by Varun G 3 · 0⤊ 0⤋
isn't calorie the heat to raise 1 gram of water by 1 C?
2006-06-20 08:42:01 · answer #2 · answered by Anonymous · 0⤊ 0⤋
1255.8 Joules
It takes one calorie to raise one gram(same as 1 mL) of water one degree celcius.
1 cal= 4.186 J.
25 grams, 12 degrees change.
4.186 * 25 * 12 = 1255.8 J
2006-06-20 08:52:58 · answer #3 · answered by Rockstar 6 · 0⤊ 0⤋
First you have to convert the degrees celcius to Kelvin by adding 273, then use the formula (P1*V1)/T1 = (P2*V2)/T2
Only, the V has to be inliters, so convert the gram to Liter by first converting it to moles.
2006-06-20 08:42:25 · answer #4 · answered by Spork5000 2 · 0⤊ 0⤋
I probably could have done it a month ago but schools out and my brain is wiped clean of any and all chemistry.
2006-06-20 08:42:29 · answer #5 · answered by c_c_runner88 3 · 0⤊ 0⤋