2006-06-20 08:24:46 · 13 answers · asked by david c 4 in Sports ➔ Basketball
Stockton
Guys, do me a favor, answer this question for me.
http://answers.yahoo.com/question/index;_ylt=Aoh127ND0nkthDNCefPeNLjzy6IX?qid=20060618213803AAFZcOr
2006-06-20 08:28:00 · answer #1 · answered by Malcolm uses Xbox 360 Avatar 7 · 2⤊ 3⤋
Definitely, Magic Johnson. He revolutionized the point guard position. As a 6'8" guard, he was almost impossible to defend. One of the greatest passers and ran the Laker fast break to perfection. He just made everyone around him a much better player.
2006-06-20 22:56:53 · answer #2 · answered by Hoopfan 6 · 0⤊ 0⤋
John Stockton mos def! Averaging 3 steals a game and a whole $hitload of assists
2006-06-20 15:30:37 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Maurice Cheeks
2006-06-20 15:36:40 · answer #4 · answered by g_jeramy 2 · 0⤊ 0⤋
for once i agree with ya'll.. either magic or stockton fasho
didn't mention mj cuz he wasn't a true PG.. i know he played 2 at times.. maybe even 3
2006-06-20 15:33:38 · answer #5 · answered by do it movin' 1 · 0⤊ 0⤋
Stockton or Big-O
because Stockton played very well and had a lot of assists and Big-O because he averaged a triple-double in a season in the 60's, i think
2006-06-20 15:37:51 · answer #6 · answered by totalstuff8 2 · 0⤊ 0⤋
Magic Johnson, some say the BIg-O but i give it to Magic since he did play center for the Lakers in a little game once.
2006-06-20 15:28:00 · answer #7 · answered by The Angry Stick Man 6 · 0⤊ 0⤋
Magic Johnson.
Did Stockton rival Larry Bird and Michael Jordon? I don't think so.
2006-06-20 16:11:17 · answer #8 · answered by Big Z 6 · 0⤊ 0⤋
Its a matter of opinion ...but John Stockton or Magic
2006-06-20 15:45:51 · answer #9 · answered by jmpshtr101 2 · 0⤊ 0⤋
Jerry West, steve nash, stockton, and magic...
2006-06-20 15:28:49 · answer #10 · answered by Benz 4 · 0⤊ 0⤋
come on people its majic, the man was 6.5 and could pass like no one ive ever seen. go watch some clips and you will see
2006-06-20 19:56:28 · answer #11 · answered by okufor04 2 · 0⤊ 0⤋