How is this done 6(x+1)=12(x-3)?

Question

I'M TAKING THE ENTRANCE EXAMINE FOR NURSING ,CAN SOMEBODY HELP WITH THIS PROBLEM

Answer 1

:)
Open by multiplying you have
6x + 6=12x – 36
Move the unknown to the left side and all known values to right. DO NOT forget to change their signs as you do that. Now you have
6x-12x=-6 – 36
Or
-6x=-42
x=42/6=7 (remember – divided by – is +)

Does that help?

Answer 2

This is from my 13 year daughter (currently getting an A in Honors Algebra):

6(x-1) = 12(x-3)
(now multiple the 6 by the x and the 1, then the 12 by the x and the 3)
6x+6 = 12x - 36
(now get rid of the 6)
6x+6-6 = 12x - 36 - 6
(this is your new equation step)
6x= 12 x -42 (two negatives are added together, not subtracted)
(now get rid of the 12)
6x -12x = 12x -12x -42
(this is your new equation step)
-6x = -42
(now solve for x)
-6x/-6 = -42/-6
(this is your answer)
x = 7 (negative divided by a negative is a positive)

This is quote - unquote from my daughter. I used to know how to do these, but now I have to ask the child, smile.

Answer 3

If you put one on top of the other 6x + 2y = -1 12x - y = 3 You can see how the addition method works. You can either multiply the top row by -2 (to get rid of the x and solve for y) or multiply the bottom row by 2 (to get rid of the y and solve for x). Let's try the first: Multiply top equation by -2: -2(6x + 2y = -1) -12x - 4y = 2 So now you have: -12x - 4y = 2 12x - y = 3 ------------------------- Add them together (12x and 12x cancel out) -5y = 5 Divide by -5: y = -1 Now plug y = -1 into second equation: 12x - y = 3 12x - (-1) = 3 12x + 1 = 3 Subtract 1 from both sides: 12x = 2 Divide by 12: x = 1/6 Answer: x = 1/6, y = -1

Answer 4

An equation is like a kids' teeter-totter with the = sign as the pivot. Both sides have to be balanced. You can shift stuff around, so long as you shift on both sides.

First thing is to get rid of the () on both sides:
6(x+1)=12(x-3) is the same as 6x+6=12x-36

Now, you need the x's on one side and the numbers on the other:
6x-12x+6 = 12x-12x-36 OR -6x + 6 = -36 OR -6x = -42

Now you need to find X. Divide both sides of the equation -6x = -42 by -6 for your answer, which would be x=7.

Answer 5

6(x) + 6(1) = 12(x) + 12(-3)
6x + 6 = 12x - 36
6x + 36 + 6 = 12x - 36 + 36
6x + 42 = 12x
6x - 6x + 42 = 12 - 6x
42 = 6x
6x = 42
6x/6 = 42/6
x = 7

proof

6(x + 1) = 12(x - 3)
6(7 + 1) = 12(7 - 3)
6(8) = 12(4)
48 = 48

Answer 6

6(x + 1)= 12 (x -3)

You are trying to "solve for x", so what you need to do is to get x on one side of the equation, and numbers of the other:

So first write it all out;

6(x+1) is the same as (6 x X) + (6 X 1) or "6x + 6"

similarly 12(x-3) is 12(x) - (12 X 3) or "12x -36"

Now we have 6x + 6 = 12x - 36

Add 36 to both sides, you get 6x + 42 =12x

Subtract 6x from both sides, you get 42= 6x

divide both sides by 6; you get 7=x

x is 7

Good luck.

(And good luck to Gem the Witch, too! Oops!)

Answer 7

This is for nursing?

Multiply what's outside the brackets by everything inside the brackets, keeping them separated by the signs.

6(x+1) = 12(x-3)
6x + 6 = 12x - 36

Now get all the x's on one side, and all the numbers on the other by manipulating both sides of the equation.

6x + 6 - 6 = 12x - 36 - 6
6x = 12x - 42
6x - 12x = 12x - 12x - 42
-6x = 42

Then divide both sides by -6 to get x = -7.

Answer 8

6(x+1)=12(x-3)

Multiply everything inside the brackets by the number outside:
6x+6=12x-36

Put the numbers on one side and the x's on the other side:
6+36=12x-6x
42=6x

Divide 42 by 6 to isolate for x:
x=42/6
x=7

...um, good luck with nursing.

Answer 9

6(x+1) = 12(x-3)

6x + 6 = 12x - 36.

36 + 6 = 42.

Now you have :
6x + 42 = 12x

12x- 6x= 6x

Now you have:
42= 6x

42/6 = 7

x= 7.

Answer 10

x = 7