What do the directions say? Are you supposed to solve for y?
8x + 52y - 572 = 0
Subtract 52y from each side
8x - 572 = -52y
Divide each side by -52
(8/-52)x - 572/-52 = y
y = (-2/13)x + 11
2006-06-20 08:08:11
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answer #1
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answered by MsMath 7
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It's not an equation to be solved, but an equation that represents a line in the Cartesian plane. It is easier to graph when solved for y. So...if 8x+52y-572=0,
then 52y=-8x+572,
then y=-2x/13+11.
Plugging in various values for x, we get different y-values that can be plotted on the plane. Points are written as (x,y). The x-axis runs horizontally and the y-axis runs vertically. One point on the line is (13, 9). The coefficient of the x in the equation, -2/13, is the slope (m) of the line in the form of rise/run. (As you go 13 units to the right, you also go 2 units down.) The other constant, 11, is the y-intercept (b). (The line intersects the y-axis when y=11, or the point (0,11) is on the line.)
2006-06-20 08:15:03
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answer #2
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answered by Anonymous
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You cannot solve (ie, find a numerical answer for the variables) in a 2-variable system with only one equation. There are actually infinite answers. This is an example of this type of equation:
x+y-4=0
Here are some solution sets:
x=0, y=4 x=4, y=0 x=-4, y=8 x=-5, y=9 x=-6,y=10
As you can see, any two x and y that yield a difference of 4 will work here.
The only thing you can do is express one variable in terms of the other.
To express x in terms of y, move the constant (-572) and the y-term (52y) to the right side, and divide through by 8:
x=(143-13y)/2
The reverse is true to express y in terms of x:
y=11-(2/13)y
2006-06-20 08:22:32
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answer #3
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answered by Veritatum17 6
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Umm what math class are you taking? to me, that problem is impossible to solve. Is their anyway for you to change the equation so you are only solving for one variable?
2006-06-20 08:06:23
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answer #4
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answered by zbbasktbal82092 3
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as it stands, pretty much all you can do is solve for x in terms of y or vice versa. is it possible you're leaving something out in asking the question?
2006-06-20 08:09:14
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answer #5
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answered by Clark S 1
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factor and solve for x to make the equation true (x makes the equation zero)
2006-06-20 08:20:20
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answer #6
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answered by Anonymous
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I suggest you make x = y (move y to the other side) and graph it.
2006-06-20 08:05:58
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answer #7
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answered by cyanne2ak 7
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I dunno I hate math.
2006-06-20 08:06:14
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answer #8
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answered by c_c_runner88 3
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