How do you synthesize lanthanum oxysulfide?

Question

It needs to be in an aqueous environment. I know how to synthesize La2O3, but I need to exchange one of the oxygens with a sulfur to get La2O2S.

Answer 1

See source.

Y Jiang, Y Wu, Y Xie, Y-T Qian, 2000, Synthesis and Characterization of Nanocrystalline Lanthanide Oxysulfide via a La(OH)3 Gel Solvothermal Route. J. Am. Ceram. Soc. v 83 p 2628

Abstract:

A La(OH)3 gel solvothermal process has been developed for the preparation of nanocrystalline lanthanide oxysulfide (La2O2S) in polar solvents at 300°C through a reaction between a La(OH)3 gel and K2S. X-ray powder diffraction (XRD) indicated that the product was hexagonal La2O2S with cell parameters a = 4.046 Å and c = 6.951 Å. Transmission electronic microscopy (TEM) showed that different morphology nanocrystallites were formed, including particles with diameters of about 10 nm and nanorods about 10 nm in diameter and 300 nm in length, depending on the solvent.

Answer 2

You made me nuts with this... hope ur happy :D

The number of found molecules equals 4.
They are as follows:

La2O3, SO2, La2O2S2, O2,

The number of hypothetical elements equals 3.
They are as follows:

La, O, S,

Let`s assume that the coefficient before the last
molecule equals one. The equation is as follows:

a La2O3 + b SO2 + c La2O2S2 = O2

We have to balance all elements on the both sides of the equation:

for La: 2a + 0b + 2c = 0
for O: 3a + 2b + 2c = 2
for S: 0a + 1b + 2c = 0

After finding the solution and converting the results
into smallest integers we can see that:

2 La2O3 + 4 SO2 + -2 La2O2S2 = 5 O2

We have to group appart negative and positive
coefficients to obtain the final solution:


2 La2O3 + 4 SO2 ==> 5 O2 + 2 La2O2S2