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Divide Please!!! 2x2 – 2y2/-2x2 + 2xy / (x2 + xy)?


It reads: 2x exponent 2 – 2y exponent 2 over -2x exponent 2 + 2xy DIVIDED BY (x exponent 2 + xy)

Thanks a million!!

2006-06-20 05:59:36 · 5 answers · asked by Brandon ツ 3 in Science & Mathematics Mathematics

my answers 2 choose are:

a. 2 / 3x

b. 1- / x²

c. -x² - y² / x² + xy

d. x - y / x + y

2006-06-20 06:15:52 · update #1

5 answers

I think you wrote down b wrong because the answer is 1/-x^2. here's how. (by the way, writing exponents is done by using the up arrow. i.e. x exponent 2=x^2)
((2x^2-2y^2)/(-2x^2+2xy))/x^2+xy
2(x^2-y^2)/-2x(x-y) multiplied by 1/(x(x+y)
(x+y)(x-y)/-x(x-y) multiplied by 1/x(x+y) the 2's cancel, then cross multiply
1/x(-x)
1/-x^2

2006-06-20 08:15:23 · answer #1 · answered by good knower 3 · 9 1

((2x^2 - 2y^2)/(-2x^2)) + (2xy/(x^2 + xy))

(2(x^2 - y^2)/(-2(x^2))) + (x(2y)/(x(x + y)))
(-(x^2 - y^2)/(x^2)) + (2y/(x + y))

Multiply everything by (x^2)(x + y))

((-(x^2 - y^2)(x + y)) + 2y(x^2))/(x^2(x + y))
(-(x^3 + x^2y - xy^2 - y^3) + 2x^2y)/(x^2(x + y))
(-x^3 - x^2y + xy^2 + y^3 + 2x^2y)/(x^2(x + y))
(-x^3 + x^2y + xy^2 + y^3)/(x^2(x + y))

ANS : (-x^3 + x^2y + xy^2 + y^3)/(x^3 + x^2y)

Unless you mistyped something, none of the answers you have are correct.

2006-06-20 16:39:25 · answer #2 · answered by Sherman81 6 · 0 0

2+y²/(x^4+x^3y). Do I get 20 points?

2006-06-20 13:07:55 · answer #3 · answered by bequalming 5 · 0 0

I think it's "A" for the answer to this question!!!

2006-06-20 13:29:33 · answer #4 · answered by Aleigha E 1 · 0 0

answer will be c.

2006-06-20 13:52:49 · answer #5 · answered by BoBo 1 · 0 0

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