Without the requirement about integral coefficients, we could simply write (x - 1/2)(x + 1)(x - 3) = 0, but because of that extra requirement, we multiply the first factor by 2:
(2x - 1)(x + 1)(x - 3) = 0
Multiplying that out:
(2x^2 + x - 1)(x - 3) = 0
2x^3 - 5x^2 - 4x + 3 = 0
If you need more explanation, let us know.
2006-06-20 04:55:03
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answer #1
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answered by Jay H 5
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Let f(x)=aX3(aXcube)+bX2(bXsquare)+cX+d
If 1/2,-1,3 are all roots,
it means (x-1/2) , (x+1) & (x-3) is a factor of f(x)
i.e f(1/2)=0
f(-1)=0
f(3)=0
Replacing the values in f(x)
You'll get:
f(1/2):a/8+b/4+c/2+d=0
f(-1):a+b+c+d=0
f(3):27a+9b+3c+d=0
then try to solve the eqn making 2 unknown subject of formula and using simultaneous eqn by eliminating method
2006-06-20 05:08:37
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answer #2
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answered by s13_nush 1
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roots are 1/2, -1 and 3, so
x = 1/2
x = -1
x = 3
Transpose and multiply to get integral results
2x - 1 = 0
x + 1 = 0
x - 3= 0
Multiply
(2x - 1)(x + 1)(x - 3) = 0
(2x - 1)(x² - 2x - 3) = 0
2x³ - 5x² - 4x + 3 = 0
^_^
2006-06-21 00:31:16
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answer #3
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answered by kevin! 5
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critical coefficients potential actual coefficients, which signifies that each and each one complicated roots ought to happen as conjugate pairs. all of us comprehend one root is -a million+i, so yet another should be -a million-i. alongside with the given -2, that provides us 3 roots, it really is sufficient to construct the cubic.
2016-11-15 00:42:43
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answer #4
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answered by ? 4
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(x - .5)(x + 1)(x - 3) = 0 (Multiply by 2 left and right)
(2x - 1)(x + 1)(x - 3) = 0
2006-06-20 05:15:30
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answer #5
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answered by Thermo 6
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if the roots of the equation are known...
that means
(x - root1) = 0
similarly (x - root2) = 0
and (x - root3) = 0
coz its cubic (and therefore have 3 roots)..
mutliply.. therefore for you case
(x - 1/2)(x + 1)(x - 3) = 0 is the eqaution.
2006-06-20 05:01:41
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answer #6
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answered by Varun G 3
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(2x^2 + x - 1)(x - 3) = 0
yes got it! that can be the correct equation.
2006-06-20 07:08:07
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answer #7
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answered by ♥ Riya ♥♥♥ 2
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(2x - 1)(x + 1)(x - 3)
(2x - 1)(x^2 - 3x + x - 3)
(2x - 1)(x^2 - 2x - 3)
2x^3 - 4x^2 - 6x - x^2 + 2x + 3
2x^3 + (-4 - 1)x^2 + (-6 + 2)x + 3
2x^3 + (-4 + (-1))x^2 + (-6 - (-2))x + 3
2x^3 - 5x^2 - 4x + 3
ANS : 2x^3 - 5x^2 - 4x + 3
2006-06-20 09:53:07
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answer #8
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answered by Sherman81 6
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