when you switch -x to x, you are multipling by -1. This needs to be done to both sides of the equation. One of the rules of algebra is that when ever you multiple or divide both sides of the equation by a negative number, you must flip the > to a <, or the < to a >. So...
-x > -2/3
-x * -1 < -2/3 * -1
x < 2/3
i hope that helps!
2006-06-20 04:48:10
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answer #1
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answered by celle 2
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The only way " x < -2/3" will be true is if :
x IS ALWAYS less then -2/3!
Suppose x = 1/3, then " -x = -1/3"; here "-x > -2/3" is true. But 1/3 is more than -2/3. Hence, the statement " x < -2/3" cannot be true!!
To keep the statement true for all values of x, even after switching from ">" to "<" in :
" -x > -2/3"
the new statement should read :
"-2/3 < -x"
2006-06-20 04:36:02
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answer #2
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answered by badaasaab 2
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You have it backwards.
If a negative x is greater than another negative number, it means that x is closer to zero than that other number (ie, -2 is greater than -4).
When you multiply the inequality by a negative 1 to switch the signs, the relationship doesn't change. X is still closer to zero, so x must be less than 2/3.
2006-06-20 04:22:26
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answer #3
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answered by Veritatum17 6
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Whenever you multiply or divide by a negative you must flip the inequality.
Therefore in this problem you are multiplying through by a -1.
You should get: x < 2/3.
2006-06-20 04:25:44
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answer #4
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answered by csucdartgirl 7
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both the signs switch, so x< 2/3
I think that's how it works anyway.
2006-06-20 04:21:08
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answer #5
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answered by the Politics of Pikachu 7
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I think the rule is if you divide by a negative number, you have to change the < >.
2006-06-20 04:21:37
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answer #6
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answered by mmores369 2
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u swith the signs too.
so its x<2/3
2006-06-20 04:22:52
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answer #7
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answered by Anonymous
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i think you change the -x to positive x
2006-06-20 04:21:34
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answer #8
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answered by nothankyou 5
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always when you wound up with a - number you must always have a -x
2006-06-20 04:22:09
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answer #9
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answered by terry b 2
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