judy had some raisins.she ate one and gave half to her sister.she ate another and then gave one third to her brother.she now has six left.how many did she have to begin with?
2006-06-20 02:48:09 · 24 answers · asked by DC10 1 in Science & Mathematics ➔ Mathematics
21
Lets do this problem in reverse order.
After giving 1/3 to her brother she is left with 6.
That means she has 2/3 of what she had.
that means she had 3*6/2 = 9 raisins before she gave it to her brother.
Now add one she ate. So 10.
Now she gave half to her sister that means she had 20.
Add 1 which she ate before that... so 21.
2006-06-20 02:56:10 · answer #1 · answered by Varun G 3 · 1⤊ 0⤋
21
2006-06-20 04:10:29 · answer #2 · answered by marilyn1015 1 · 0⤊ 0⤋
21
2006-06-20 03:44:35 · answer #3 · answered by VERIZONDUDE 2 · 0⤊ 0⤋
21
2006-06-20 03:24:49 · answer #4 · answered by fark 3 · 0⤊ 0⤋
21
2006-06-20 03:07:25 · answer #5 · answered by Sandra M 1 · 0⤊ 0⤋
21
2006-06-20 02:53:50 · answer #6 · answered by Anonymous · 0⤊ 0⤋
21
2006-06-20 02:53:36 · answer #7 · answered by charlie s 1 · 0⤊ 0⤋
21
2006-06-20 02:52:19 · answer #8 · answered by zharantan 5 · 0⤊ 0⤋
21
2006-06-20 02:51:43 · answer #9 · answered by nindag30 2 · 0⤊ 0⤋
21-she ate 1 and gave half to her sister which would be 10. She ate another, leaving 9 and then gave 1/3 to her brother which would be 3. So she has 6 left. Answer is 21.
2006-06-20 02:58:02 · answer #10 · answered by thegemini777 1 · 0⤊ 0⤋