There are 30 children in a class. 12 of them can play badminton, 8 of them can play table tennis. Find the greatest possible no. of children that can play neither of the 2 games.
2006-06-19 21:34:20 · 19 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Thanx but plz add the mathematical procedure also 2 win 10 points
2006-06-19 21:42:04 · update #1
Assume that those 8 that can play table tennis are part of the 12 that can play badminton, so you have 12 students that play at least one game. Everyone left over can't play either of the two games (30-12=18), so 18 students can't play anything...
2006-06-19 21:58:37 · answer #1 · answered by ditzychik508 5 · 5⤊ 2⤋
IOh, now i understand the question. Ok, there's obviously some information still missing, but if not, here's the answer: It's gonna be based on this assumption; since we want the maximum students not playing neither games, we would assume that all the 8 children that play tennis also play badminton also. This makes 8 a subset (like a child) of 12. It means the minimum of children playing a game is 12. Therefore, subtracting 12 from 30 gives 18.
18 is the max number of students not playing anything.
Take care.
2006-06-20 04:56:52 · answer #2 · answered by zzzlordcharmyzzz 1 · 0⤊ 0⤋
If the 8 out of 12 who play badminton also play TT then 30-12, 18 is the greatest possible number of children that can play neither of the 2 games.
2006-06-20 04:40:53 · answer #3 · answered by Pinky Patel 3 · 0⤊ 0⤋
To find the greatest number possible, it is assumed that those 8 who can play table tennis can also play badminton.
Thus the answer is 30-12=18
2006-06-20 04:42:22 · answer #4 · answered by canzoni 3 · 0⤊ 0⤋
12 B and 8 T
8 out of 12 B players could play Tennis. So in that worst case scenerio 18 players would be the largest number palying neither of the games
2006-06-20 04:45:02 · answer #5 · answered by Giridhar 2 · 0⤊ 0⤋
18
2006-06-20 04:47:45 · answer #6 · answered by Anonymous · 0⤊ 0⤋
you might go about this by thinking that you have to free as many children as possible so let the 8 who play TT be among the 12 who play badminton . then you are left with 18 who play nothing
2006-06-20 13:05:44 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Tot children=30
B=12
T=8
Min value of 'T and B' can be 12. This means that all the 8 children who play Tennis can also play Badminton.
Then (T and B)' = 30-12=18.
As T and B is min, (T and B)' is max.
2006-06-20 08:57:04 · answer #8 · answered by K N Swamy 3 · 0⤊ 0⤋
18
to find the greates possible number of kids playing nothing you should minimize the number of kids playing anything. you can do this by thinking that, 8 kids can play both tennis and badminton. if you think like this, it is true that 8 kids can play tennis, and 12 kids can play badminton.
the number of kids playing anything is now 12, and 30-12=18 is the numberof kids playing nothing.
hope it's true.
2006-06-20 04:44:38 · answer #9 · answered by orkunbaki 3 · 0⤊ 0⤋
being that its possible that all the children that can play tenis can also play badminton, the greatest number of children that can play neither is 30 - 12 = 18
the answer is 18
2006-06-20 05:00:22 · answer #10 · answered by simchiman 2 · 0⤊ 0⤋