Find three consecutive integers with a sum of 105?

Question

plzz help....first one with a good detailed and expalined answer gets chosen best answer...thnxxx

Answer 1

34, 35, 36. 105/3=35. They are consecutive integers so subtract 1 and add 1.

Answer 2

let the first number be 'x'. so if they are consecutive integers, the other two numbers would have to be 'x+1' and 'x+2'.

so add those together you get...
'x'+'x+1'+'x+2'=3x+3 which you want to equal 105.

3x+3=105...solve for x and you get x=34

so the numbers are 34, 35, 36.

Answer 3

34+35+36=105
(105/3)

Answer 4

x+(x+1)+(x+2) = 105
3x + 3 = 105
3x = 105-3
x = 102/3
x=34
=> x1 = 34
x2 = 35
x3 = 36

Answer 5

let the three consecutive nos be x-1, x, x+1

There sum i.e. (x-1)+(x)+(x+1)= 105

3x= 105
x = 105/3
x=35

the other two numbers are (x-1) i.e. (35-1)=34
& (X+1) i.e. (35+1) = 36

Hence the three consequitive numbers are 34,35,36

Answer 6

x + (x+1) + (x+2) = 105
regroup
x + x + x + 1 + 2= 105
consolidate
3x + 3 = 105
subtract 3 from both sides
3x = 102
divide both sides by 3
x = 34
x + 1 = 35
x + 2 =36

Answer 7

Let x = the first integer.

Then (you figure it out) = the next consecutive integer,
and (you figure it out again) = the third consecutive integer.

If their sum is 105, then

(you figure it out) + (you figure it out) + (you figure it out) = 105.

Solve the equation!

I bet your textbook has some similar (solved) examples. Use them as a model.

Answer 8

34, 35, 36