2006-06-19 11:11:53 · 6 answers · asked by rjkoedel 1 in Home & Garden ➔ Do It Yourself (DIY)
Ok, the pool is 18 foot in diameter and the height is 48"...so, lets figure this out...
3.14 X 9 X 9 X 4 X 7.48 = 7609.853 gallons.
pi X r2 X height X gallons/cubic foot.
Thats figuring that you have the pool filled to the brim, anything less, then you simply subract
3.14 X 9 X 9 X .0833 X 7.48 = 158.5386 gallons per inch.
You will remove 158.5 gallons per every inch that you have it below 4 feet...
Ohio Class III Waste Water Treatment Plant Operator
27 years experience, (recently retired).
I wish you well..
Jesse
2006-06-19 15:06:37 · answer #1 · answered by x 7 · 0⤊ 0⤋
Like the other answers - how deep is the pool ?? Figure there are approximately 5.3 gallons per cubic foot. Take 18' x 48' x the depth = x cubic feet. Multiply x cubic feet x 5.3 gallons/cubic foot = total gallons. Try another answer - if the pool is 18" high x 48" in diameter it would be: 1.5' x 2.0' x 2.0' x 3.1416 (pi x r2) = 18.85 cubic feet x 5.3 = 100 gallons of water. Good luck !!
2006-06-19 18:43:26 · answer #2 · answered by retepsumdac 3 · 0⤊ 0⤋
I am assuming the pool is 18' round x 48" deep. Normal capacity is 6,660 gallons and maximum capacity is 7,611 gallons
2006-06-20 08:37:15 · answer #3 · answered by deg4853 3 · 0⤊ 0⤋
till it fills to the top
2006-06-20 16:10:16 · answer #4 · answered by Anonymous · 0⤊ 0⤋
it depends on how deep it is
2006-06-19 18:15:16 · answer #5 · answered by pixxie179 3 · 0⤊ 0⤋
How deep is it?
2006-06-19 18:14:57 · answer #6 · answered by Don E 4 · 0⤊ 0⤋