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if so then solve this problem...
A balloon starts rising from ground with upward acceleration 2m/s^2.After 1s, a stone is dropped from it.Time taken by stone to strike ground is ?explain the whole process.

2006-06-19 08:41:33 · 11 answers · asked by Anonymous in Science & Mathematics Physics

11 answers

After 1s, velocity of baloon is -2m/s (- as it is going against earth gravity). As stone is dropped from the baloon, it will have same velocity.
Distance travelled by baloon in 1s is: 1m
Therefore: s = ut + 1/2 a*t^2
1 = -2*t + 1/2*10*t^2 (taking acc due to gravity, g = 10)
1 = -2t + 5t^2
5t^2 - 2t - 1 = 0
t = (2 +/- sqrt(4 + 20))/10
t = (2 +/- 4.9)/10
t = (2 + 4.9)/10 = 0.69 sec
(neglecting - coz negative t is not possible)

2006-06-19 08:57:36 · answer #1 · answered by Varun G 3 · 3 3

Sharp enough to know you're cheating on your homework.

I'll help get you started though:

Calculate the distance the balloon will rise in 1 s, (h)
Calculate the upward velocity of the balloon after 1 s of acceleration at 2 m/s^2, (v)
When the stone is released, it will have the upward velocity of the balloon v and will be at a height h. Figure how long it takes a rock starting at h and with an initial upward velocity of v to fall to the ground given the downward acceleration of gravity (9.81 m/s^2).

The mass of the stone doesn't matter.

2006-06-19 15:47:21 · answer #2 · answered by Hillbillies are... 5 · 0 0

The distance formula for an initial velocity of zero and an initial displacement of zero is D = 1/2at^2

And the velocity after time t is just v = at.

So, when released from the balloon, the rock is 1 meter off the ground and has an initial velocity of 2. And, it's new acceleration is -9.8 m/s^2.

The general displacement equation with an initial velocity and an initial displacement is: D = D(0) + V(0)t + 1/2at^2. We want to know how long it takes for the rock to hit the ground. Well, the distance above the ground is zero when you hit the ground. I know, it sounds stupid, but it is a good way to remember how to use the formula. Ok, setting D = 0 and solving:
0 = 1(m) + 2 (m/sec)* t sec + (-9.8 m/sec^2)*t^2 sec^2.

Using the quadratic, t = (-2 +/- sqrt(4+4*1*9.8))/2 =
-1 +/- sqrt(43.2)/2 = -1 +/-sqrt(10.8). We throw out the negative time solution and we get t = sqrt(10.8) - 1. Or, about 2.3 seconds.

2006-06-19 16:10:11 · answer #3 · answered by tbolling2 4 · 0 0

The weight of the stone is irrelevant, it will fall at 32 feet per second. the answer is simple enough because all the variables are already present...don't over think the answer.

2006-06-19 19:39:38 · answer #4 · answered by William 2 · 0 0

Seriously, you have all the information to solve this from you other answers, you're just being lazy now. Do your homework. It's not even hard anymore. Everyone has explained the equation to you. Hop to it. I believe in you.

2006-06-19 15:50:02 · answer #5 · answered by TheHza 4 · 0 0

d=vit+.5at^2
d=0+.5(2)(1^2)
d= 1m

d=vit+.5at^2
1=0+.5(9.81)(t^2)
t^2= .20387

i don't have a calculator with me but you can get the answer by finding the square root of .20387

oh yeah
Hillbillies, I hope you were joking

2006-06-19 23:48:15 · answer #6 · answered by Rajan 3 · 0 0

u need the weight of the stone

2006-06-19 15:44:19 · answer #7 · answered by dirtee diamondz 3 · 0 0

Hmmm, sounds like home work. The answer is one second. you do the math. (Hint, how fast does stuff like a rock fall)

2006-06-19 15:57:21 · answer #9 · answered by vmmhg 4 · 0 0

i don't knoe the answer but i know that u r a fan of hilary duff..i think

2006-06-20 02:33:56 · answer #10 · answered by ♀guardian of angels♀ 3 · 0 0

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