solve it ...?

Question

A particle starts moving with acceleration 2m/s square,distance travelled in 5th half second is?explain the whole process..

Answer 1

I assume it's starting from zero speed? If so,

d = v1t + 1/2at^2
after 2 seconds (i.e. 4 half-seconds), it's travelled
d = 0(2) + 1/2(2)(2)^2
= 0 + 1/2 * 2 * 4
= 4m

after 2.5 seconds (i.e. the fifth half-second), it's travelled
d = 0(2.5) + 1/2(2)(2.5)^2
= 0 + 1/2 * 2 * 6.25
= 6.25 m

So in the last half-second, it's travelled 6.25 - 4 = 2.25m.

Answer 2

Dave Stark gave you this equation in your last question,
it's d=v(i)t+at^2
v(i)=initial velocity-since it's not stated, I would use 0
a=2 m/s^2
t=5/2s (if I understood your question)
d=distance.
Plug those numbers in,
Then subtract how far it had gone in the time up til 5/2
So plug in 4/2 m/s^2 to the same equation. Subtract the second d that you got from first and you'll have how far it went in that 1/2 s.

Answer 3

First off are you using a particle accelerator.

Answer 4

Pia;

I gave you the necessary equations just a few minutes ago. think about it for a minute, and then use them:

d = vt
d = at^2

and a new one: v = at

Answer 5

it should be 20 meters

Answer 6

to tell ya the truth i dont know