Since you use log rather than ln, I assuming base 10 (common) logs.
Logrithms are exponents!!!!!
They are the exponent you hang on the base to get the number in question. That is, saying log x = y is the same as saying 10^y = x.
So log x = -2 is the same as saying 10^(-2) = x or x = 1/100.
2006-06-19 07:55:44
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answer #1
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answered by rt11guru 6
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Solve Log
2016-09-29 22:20:13
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answer #2
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answered by Anonymous
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When using log, it is in base 10.
log a = b can be written as 10^b=a
So log x = -2 can be written as 10^(-2) = x
Therefore x = 1/(10^2) = 1/100
2006-06-19 10:06:29
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answer #3
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answered by Y L 2
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This Site Might Help You.
RE:
How do you solve log x=-2?
2015-02-03 03:58:34
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answer #4
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answered by Anonymous
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For the best answers, search on this site https://shorturl.im/Ublk1
log(x^2)=2log(x) 2log(x)=log(x)^2 means log(x)[2-log(x)]=0. Thus either log(x)=0 or log(x)=2 If log(x)=0 then x=1. If log(x)=2 then x=100
2016-03-25 21:55:12
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answer #5
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answered by Anonymous
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log x = -2
This is read as "The logarithm of x with base 10 is equal to -2."
This can also be read as "10 raised to the -2 power equals x."
Therefore, 10^-2 = 1/100 = 0.01 = x.
2006-06-19 08:05:11
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answer #6
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answered by Baseball Fanatic 5
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assuming there is no base to worry about
log(x) = -2
inverse log both sides
x = 10^-2
x = .01
2006-06-19 12:07:53
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answer #7
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answered by Sherman81 6
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log (base) x= -2
therfore
x= base^-2
this base can be 10 or any number
2006-06-19 08:14:17
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answer #8
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answered by Vivek 4
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log x = -2
convert into exp. form:
x = 10^-2
x = 0.01
^_^
2006-06-20 00:08:47
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answer #9
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answered by kevin! 5
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log a = b <=> a=e^b
therefor x=e^-2=0.1353...
(presuming this is the natural logarithmus; the process is the same anyway).
2006-06-19 08:04:09
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answer #10
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answered by newtonvolt 2
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