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2006-06-19 07:49:14 · 7 answers · asked by bombay2pac2000 1 in Science & Mathematics Mathematics

7 answers

Since you use log rather than ln, I assuming base 10 (common) logs.

Logrithms are exponents!!!!!
They are the exponent you hang on the base to get the number in question. That is, saying log x = y is the same as saying 10^y = x.

So log x = -2 is the same as saying 10^(-2) = x or x = 1/100.

2006-06-19 07:55:44 · answer #1 · answered by rt11guru 6 · 2 0

Solve Log

2016-09-29 22:20:13 · answer #2 · answered by Anonymous · 0 0

When using log, it is in base 10.

log a = b can be written as 10^b=a

So log x = -2 can be written as 10^(-2) = x
Therefore x = 1/(10^2) = 1/100

2006-06-19 10:06:29 · answer #3 · answered by Y L 2 · 2 0

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RE:
How do you solve log x=-2?

2015-02-03 03:58:34 · answer #4 · answered by Anonymous · 0 0

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log(x^2)=2log(x) 2log(x)=log(x)^2 means log(x)[2-log(x)]=0. Thus either log(x)=0 or log(x)=2 If log(x)=0 then x=1. If log(x)=2 then x=100

2016-03-25 21:55:12 · answer #5 · answered by Anonymous · 0 0

log x = -2

This is read as "The logarithm of x with base 10 is equal to -2."
This can also be read as "10 raised to the -2 power equals x."

Therefore, 10^-2 = 1/100 = 0.01 = x.

2006-06-19 08:05:11 · answer #6 · answered by Baseball Fanatic 5 · 0 0

assuming there is no base to worry about

log(x) = -2
inverse log both sides
x = 10^-2
x = .01

2006-06-19 12:07:53 · answer #7 · answered by Sherman81 6 · 0 0

log (base) x= -2
therfore
x= base^-2
this base can be 10 or any number

2006-06-19 08:14:17 · answer #8 · answered by Vivek 4 · 0 0

log x = -2

convert into exp. form:
x = 10^-2
x = 0.01

^_^

2006-06-20 00:08:47 · answer #9 · answered by kevin! 5 · 1 0

log a = b <=> a=e^b
therefor x=e^-2=0.1353...
(presuming this is the natural logarithmus; the process is the same anyway).

2006-06-19 08:04:09 · answer #10 · answered by newtonvolt 2 · 0 0

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