there is no water underneath it. The block is released. Will it rise to the surface or stay where it is?
2006-06-19 05:07:41 · 12 answers · asked by jj23 1 in Science & Mathematics ➔ Physics
Weather the wood will stick to the bottom depends on the buoyancy force (density of wood) and the vacuum suction you have created between the contact surfaces (porosity of wood).
As you press the smooth side of wood to the smooth surface of the tank bottom you will create a vacuum by displacing water between contact surfaces.
2006-06-19 05:12:46 · answer #1 · answered by Edward 7 · 0⤊ 0⤋
When the downward pressure on the wooden block is released water due to its freeflowing ( not viscous flow) nature will enter underneath the wooden block and will thrust the wooden block upwards.As the specific gravity of wood is less than water the wooden block will ultimately rise to the surface of water and will float.
2006-06-19 05:31:59 · answer #2 · answered by zabardast 1 · 0⤊ 0⤋
I wouldn't say that it's safe to assume that the fish is dead. You know what they say about assuming. (: Anywho. The best way to tell is to do the obvious- tap the tank, gently move some of the water in the tank, drop a bit of food around him, and check for any gill or fin movement. As far as the cause for such behavior, that in itself is rather tricky to uncover. It could honestly be from a variety of things, some of which depend on the type of goldfish he is, and most of which are nearly invisible to the eye. He might also be suffering from ammonia poisoning or the effects of your changing all of the water unless you did a partial change. If not suffering from that, perhaps an internal parasite is the culprit. Do your homework (if he is alive) and keep a close eye on him to notice any signs of such an issue and then take immediate action (buying medicated food and other remedies) to cure him. Honestly, I would recommend checking your filter/air pump systems and doing another partial water change and waiting it out as your best bet.
2016-03-26 21:35:57 · answer #3 · answered by ? 4 · 0⤊ 0⤋
Since there is no water underneath the wooden block, if u draw the FBD(free body diagram) of the block there will be no forces acting on the block upwards(the normal reaction from the bottom of the floor will be balanced by the weight of the bllock), so the block cannot move upwards.
2006-06-19 05:42:35 · answer #4 · answered by tS 2 · 0⤊ 0⤋
Depending on the type of wood, but most would still rise to the surface. There would still be water beside the block which would cause it to rise.
2006-06-19 05:11:00 · answer #5 · answered by Nate 3 · 0⤊ 0⤋
If the bottom of the tank was perfectly smooth and the bottom of the peace of wood was perfectly smooth it is possible to get a suction cup type of effect. In practice this would be hard to achieve.
2006-06-19 05:16:50 · answer #6 · answered by georgephysics13 3 · 0⤊ 0⤋
It will rise. The wood is porous enough that it probably wouldn't cause a vacuum to form under the block.
2006-06-19 05:11:03 · answer #7 · answered by David T 4 · 0⤊ 0⤋
It is difficult to keep the wood in contact with the tank with out any additional weight or with out using gum like thing to keep it contact.
If you use any of the above, then there is no possiblity of wood going up.
2006-06-19 05:42:00 · answer #8 · answered by Pearlsawme 7 · 0⤊ 0⤋
IT WILL RISE TO THE SURFACE---REASON BEING THERE IS STILL AIR INSIDE THE BLOCK OF WOOD CAUSING IT TO RISE
2006-06-19 05:13:27 · answer #9 · answered by dolls7949 2 · 0⤊ 0⤋
Most types of wood will rise to the top. Only "ironwood" and wood that is rotten or waterlogged will not float.
2006-06-19 05:09:41 · answer #10 · answered by Blue Jean 6 · 0⤊ 0⤋