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Two identical balls of same weight are dropped from top of a building
one on smooth concrete ground and the other on a smooth rubber pad.Which ball will bounce more?

2006-06-19 04:54:16 · 5 answers · asked by zabardast 1 in Science & Mathematics Physics

5 answers

Smooth concrete - elastic collision!!!
The total kinetic energy of the system remains the same before and after the collision, (though some deformation and loss of kinetic energy takes place). If you hear any two object colliding, that means that some kinetic energy has been lost to the system. The ball will transfer some of its kinetic energy into the rubber pad therefore having a significant decrease in speed. Therefore, the ball will bounce more if dropped on the smooth concrete.

2006-06-19 05:13:35 · answer #1 · answered by Nikki 1 · 0 0

The one dropped on concrete floor. The bounce height depends on the co-efficient of restitution. Which is 1 for a perfectly elastic collision and 0 for an inelastic collision. The co-efficient is measure of the measure of the elasticity in a collision. In this case the co-efficient is greater for ball & concrete floor(more elastic collision with the ball) thus more bounce height.

In a collision with rubber floor, more KE is lost as rubber floor deforms more than concrete one during collision.

2006-06-19 05:28:52 · answer #2 · answered by muks320 3 · 0 0

I would say the concrete would cause the ball to bounce higher.

I would think that the rubber floor would absorb more of the kinetic energy of the ball... i.e. the ball wouldn't compress as much as it would if it hit the concrete.

2006-06-19 05:01:08 · answer #3 · answered by imrational 5 · 0 0

Concrete.
Rubber pad absorbs the energy of the rubber ball and prevents it from bouncing higher.
concrete is harder so it will make the ball bounce higher.

2006-06-19 05:07:07 · answer #4 · answered by Anonymous · 0 0

The rubber pad. More elastic collision, less energy lost.

2006-06-19 04:58:55 · answer #5 · answered by timtheenchanter 2 · 0 0

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