The first one to answer this question gets 10 points.
2006-06-19 03:54:29 · 14 answers · asked by Vanchit S 2 in Science & Mathematics ➔ Mathematics
(0! +0! + 0! +0! +0!)!
2006-06-19 03:57:33 · answer #1 · answered by rt11guru 6 · 1⤊ 2⤋
you cant from using only 5 zeros but you can do this 0-10-0-10-0-10-0-10-0-10=70
simplifies down to 120
2006-06-19 06:01:44 · answer #2 · answered by bill f 3 · 0⤊ 0⤋
Though someone already said it and with the correct answer which is (0!+0!+0!+0!+0!)! = 120.
2006-06-19 04:02:11 · answer #3 · answered by conradj213 7 · 0⤊ 0⤋
Well, we know, 0! = 1
Thus, 0!+0!+0!+0!+0! = 1+1+1+1+1 = 5
5! = 5*4*3*2 = 120
Solved
2006-06-19 03:59:43 · answer #4 · answered by organicchem 5 · 0⤊ 0⤋
rt11guru up there has the right answer
(0! +0! + 0! +0! +0!)! = 120
2006-06-19 04:00:29 · answer #5 · answered by dhaval70 2 · 0⤊ 0⤋
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2016-11-14 23:33:19 · answer #6 · answered by ? 4 · 0⤊ 0⤋
[(0^0)+(0^0)+(0^0)+(0^0)+(0^0)]!=120
(1+1+1+1+1)!=5!=1*2*3*4*5=120
Oh sorry ! I think i used ten 0`s but you know i think there is no diffrence between ten 0`s and five 0`s !
Both means nothing !
So ... here your answer ! Please choose my answer as the best !
Please ! I need it !
2006-06-19 04:10:35 · answer #7 · answered by Third eye 2 · 0⤊ 1⤋
(0!+0!+0!+0!+0!)!=120
2006-06-19 03:57:52 · answer #8 · answered by peachmonk 4 · 0⤊ 0⤋
(0!+0!)^7-(0!x(0!+0!))^3
equals:
2^7-2^3
which equals:
128-8
=120
(0!+0!+0!+0!+0!)! also works!
Hope this helps!
2006-06-19 04:04:10 · answer #9 · answered by quickster94 3 · 0⤊ 0⤋
I am not a mathematician, but it seems to me that if you start with any number of zero's you cannot get anything else from them.
2006-06-19 03:58:40 · answer #10 · answered by Anonymous · 0⤊ 0⤋