2006-06-19 02:44:03 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Crazydeadmoth got the hard half of the answer, but missed the easy half.
The obvious solution is when x = PI/2 or 90 degrees.
The complete solution between 0 and 2pi is .284 radians and pi/2 (1.571 radians).
2006-06-19 03:12:08 · answer #1 · answered by Bob G 6 · 0⤊ 0⤋
4sinx + 3cosx = 43
2006-06-23 10:31:13 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Divide by 5 and recognise the left hand side as sin(x+y) where cos(y)=4/5. This gives
x=sin^(-1)(4/5) - cos^(-1)(4/5).
To get all of the solutions, you have to take into account periodicity of the sin and cos functions.
2006-06-19 10:00:19 · answer #3 · answered by mathematician 7 · 0⤊ 0⤋
Well the obvious answer is x=90 °. So sin(x)=1 and cos(x)=0
2006-06-19 10:06:10 · answer #4 · answered by deflagrated 4 · 0⤊ 0⤋
X = [2n+0.5](pi) or 2n(pi)+16degrees
Hint: Divide LHS and RHS by 5
then convert 4/5 and 3/5 to their respective sine and cosine
then simplify and solve for x
2006-06-19 09:58:52 · answer #5 · answered by mohit 2 · 0⤊ 0⤋
x = 90° or 16.2602°
2006-06-19 12:19:24 · answer #6 · answered by Sherman81 6 · 0⤊ 0⤋
(n)2pi+.284 where n goes from 0 to infinity
so th answer is
.284
6.567
12.8
.....etc
2006-06-19 09:51:11 · answer #7 · answered by CRAZYDEADMOTH 3 · 0⤊ 0⤋
what are you solving FOR? I can't help you unless you're specific.
2006-06-19 09:52:19 · answer #8 · answered by AnGeL 4 · 0⤊ 0⤋
x={16.26, 90} degrees +360*n where n=+/-0,1,2,3....
2006-06-19 15:57:04 · answer #9 · answered by Anonymous · 0⤊ 0⤋
no i thing its wrong
2006-06-19 09:50:07 · answer #10 · answered by ninin a 1 · 0⤊ 0⤋