arctan x should be interpreted as "the angle whose tangent is x". So draw a right triangle and include an angle whose tangent is x. Then figure out the sine of that angle in terms of x and you're done.
Easiest way to do this is to let the side opposite the angle be x and the side adjacent to the angle be 1. Then the hypotenuse will have length sqrt(1+x^2).
2006-06-19 11:11:53
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answer #1
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answered by Bill Lumbergh 4
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The previous poster was wrong. The notation arctan x means the inverse function for tan x. In other words, it undoes the tangent.
Your function takes a number x, finds the angle whose tangent is x and then takes the sine of that angle. In other words, if tan(A)=x, what is sin(A)? If you draw a triangle showing the relation tan(A)=x, then you should be able to find sin(A) in terms of x. But you must use a pythagorean identity to do so.
2006-06-19 09:49:18
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answer #2
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answered by mathematician 7
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No sin and arctan x is worlds apart.
2006-06-19 10:19:21
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answer #3
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answered by Kenneth Koh 5
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well tan is equal to sin/cos so arctan or tan^(-1) is equal to cos/sin so sin is not equal to arctan
2006-06-19 09:43:04
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answer #4
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answered by CRAZYDEADMOTH 3
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no, two totally different functions.
2006-06-19 09:40:50
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answer #5
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answered by drewK 3
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