ok another physics question..?

Question

calculate the heat energy required to raise the temperature of 16g of water from 11degrees celsius to 46degrees celsius

Answer 1

sp ht of H2O = 1 cal/g C

Heat = mass (sp ht) (change in temp)

Q = m (sp ht) (t2 - t1)

Q = 16 g (1 cal/g C) (46 C - 11C)

Q = 560 cal

or

Q = 560 cal (4.187 J / cal)

Q = 2345 J

Answer 2

The heat energy required to raise the temperature of 16g of water from 11degrees celsius to 46degrees celsius is the 0.1% of that heat required to change this world.

Answer 3

Q=c*m*delta(t)=(4.2*10^3)*0.016*(46-11)=2352 J

Answer 4

Equation is
Q1-Q2=m x s x (t1-t2)
= 16 x 1 x(35)
=560 calories.

Answer 5

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Answer 6

mass=0.0164
specific heat of water=4190J/kg
change in temperature=(46-11)=35
heat energy,Q=m.c.t=0.016.4190.35
=2346.4J

Answer 7

1j/gdegC * 16g * 35 degC = 560 joules

Answer 8

560 calaries

Answer 9

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