Both are parallel lines. There is no solution
2006-06-18 17:02:21
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answer #1
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answered by peaceharris 2
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These lines, y=-x+6 and y=-x+3 are parallel lines. The slopes of these lines is -1. So the angle with which these lines intersect the x axis is -45 degree (tan -45 = -1). If you give the value 0 for x in both these equations, y = 6 and y = 3, respectively. Thus, these lines intersect the y axis at 6 and 3, respectively.
2006-06-19 00:54:05
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answer #2
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answered by K.J. Jeyabaskaran K 3
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You have to graph it. That can't be done here unless someone bothers to put it up on a website and link to it. I'm not sure how you're supposed to graph it, anyway. You can solve it and then graph it. Solve it by substituting terms. You know that y=3-x, so put 3-x in for y in the first equation and solve for x.
2006-06-19 00:00:36
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answer #3
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answered by cucumberlarry1 6
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x + y= 6
y= 6-x
Possible Values of X= 1, 2, 3
Possible Values of Y= 5, 4, 3
Coordinates: (1,5); (2,4); (3,3)
y=3-x
Possible Values of X= 1, 2, 3
Possible Values of Y= 2, 1, 0
Coordinates: (1,2) (2,1) (3,0)
One u got the coordinates, just mark them on the graph. The point at which they meet at X-Axis will be the solution for X and vice versa
2006-06-19 00:15:22
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answer #4
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answered by Dhruv Kapur 2
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You first have to put it on the graph by fing the slope and plugging in coordinates. Then you "connect the dots". If you need to find the intersection, look at where the lines of the equations intersect. The y intersept for the first one is (6,0) and the x intercept is (0,6). The y int. for the second is (3,0) and the y int. is (0,3). Hope this helps, MayMay
2006-06-18 23:59:34
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answer #5
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answered by MayMay 2
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first you do the y = mx + b
y = -x +6 and y = -x +3
then you start graphing from there,
at y = 6, go down 1 and right one, place a mark and draw.
and at y = 3, go down 1 and right 1, place a mark and draw.
2006-06-19 00:04:38
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answer #6
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answered by travis 2
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No solution, quite simple really. When in doubt, substitute the given for the unknown, in this case you know y=3-x, so it would be x+(3-x)=6, and it cancels out to 3=6, which we all know isnt true, so there is no solution.
2006-06-19 00:09:05
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answer #7
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answered by Chris M 1
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there is no answer to that question, since the graphic are to lines that never get crossed, since y = 3 - x is the same than y - x = 3... but u already have that y-x = 6 ... so it's imposible... by the way the are parallels,,, tho u can also check my draw:
http://img226.imageshack.us/img226/5412/lines5go.jpg
2006-06-19 00:02:08
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answer #8
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answered by LoKaZo 2
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x + y = 6
y = -x + 6
y = -x + 6
y = -x + 3
as you can see, they both have the same slope but different y-intercepts, and therefore parallel and have no solution
ANS : No Solution
For a graph, go to www.quickmath.com, click on Plot under Equations, then click on Advanced, and type in your problem.
2006-06-19 12:53:56
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answer #9
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answered by Sherman81 6
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The slopes are the same, the lines have certain distance but are parallel. So they never touch.
2006-06-19 02:28:42
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answer #10
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answered by Anonymous
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