rigid container holds a gas presure of .55 atm at the tem -100c.what will the presure be when tem inc 200c?

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rigid container holds a gas presure of .55 atm at the tem -100c.what will the presure be when tem inc 200c?

2006-06-18 12:00:28 · 2 answers · asked by Maria A. Lopez- Duarte 2 in Science & Mathematics ➔ Chemistry

2 answers

Convert temperatures to absolute; add 273 and then use Charles'law.0.55atm /173 = x /473 so x = 0.55atm times 473/173 = 1.5 atm. That's the new pressure.

2006-06-18 17:23:34 · answer #1 · answered by zee_prime 6 · 0⤊ 0⤋

rigid container => volume of the ga will stay the same. Assume this is an ideal gas, use the formula (P1)(V1)/(T1) = (P2)(V2)/(T2) = const. The tem inc 200C => the final tem = 100C (or 373K), the initial tem is 173K. Final pressure = (p1)(t2)/(t1) = .55 x 373 / 173 = 1.19 atm.

2006-06-18 19:08:45 · answer #2 · answered by Anonymous · 0⤊ 0⤋