How do u Simplify: (1/y+4)/(1/y*2)-16??

Question

I figured it out thanks to my friend and the person who said -4 was the answer. Thanks for all of your help. It is just hard trying to type a fraction problem. I do better at showing the problem on doodle in yahoo messenger.

Answer 1

[(1/y)+4)]/[(1/y^2) -16]
First simplfy the numerator.
(1/y) +4
= (1/y) +4y/y
= (1+4y)/y
then simplify the denominator.
(1/y^2) -16
= (1/y^2) - 16y^2/y^2
= (1-16y^2)/y^2
= [(1-4y)(1+4y)]/y^2
Now multiply the numerator by the reciprocal of the denominator.
(1/y+4)/(1/y*2)-16
= [(1+4y)/y] * y^2/[(1-4y)(1+4y)]
(1+4y) and y cancel
Answer: y/(1-4y)

Answer 2

You can factor the bottom so that you get (1/y+4)/(1/(y+4)(y-4)) because y^2-16 is the difference of two squares. Then flip the bottom fraction and multiply it by the top and you get (y+4)(y-4)/(y+4). Cancel the y+4's and you get your final answer: y-4. Beware though: on the graphy there will be a hole or asymptote at y=-4.

Answer 3

(1/y+4)/(1/y*2) - 16 =
(1/y+4)(y*2) - 16 =
(1/y+4) (2y) - 16 =
1/y*2y + 4*2y - 16 =
2y/y + 8y - 16 =
2 + 8y - 16 =
8y-14

so simplified version is 8y-14. Unless the definition of simplified has changed since I taught math, you can't have a variable in a denominator and call it simplified.

Answer 4

I do not see what is unclear in this problem.

1/y+4=(1+4y)/y
1/y*2=2/y (if read ad literam !!! )
[(1+4y)/y]/(2/y)=(1+4y)/2
(1+4y)/2-16=(4y-31)/2=2y-15.5 (if you prefere)

Answer 5

(2y / y+4) - 16


i'm pretty sure