You'd have to define x! for arbitrary x. Normally, it is only defined for x a non-negative integer.
Luckily, there is a standard function, the gamma function, such that gamma(n) = (n-1)! such that:
gamma(x)=(x-1)*gamma(x-1)
so gamma(x+1) is taken to be the usual extension of the factorial function to the real line.
The derivative of gamma is fairly complicated - see the source below.
2006-06-18 06:32:13
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answer #1
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answered by thomasoa 5
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The "factorial" is only defined for whole numbers, not for all real numbers. ( What does (0.5)! mean? ) The factorial, as it is usually defined, does not have a derivative...
HOWEVER! There is a nice function ( The Gamma function ) which is like a generalization of the factorial. Gamma is differentiable.
For more details see http://en.wikipedia.org/wiki/Gamma_function
2006-06-18 06:36:11
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answer #2
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answered by AnyMouse 3
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x! normally only works for integer numbers, a discrete, and hence non-continuous series, and those things doesn't have derivatives.
You must first define a continuous function f such that f(x) = x! for all integer x, and then (f(x)/f(x-1) = x) for all other numbers. That can be tricky!
2006-06-18 09:43:11
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answer #3
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answered by User1 2
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