English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

tempature was approx 90 deg. F

2006-06-18 02:56:17 · 2 answers · asked by dan j 1 in Science & Mathematics Physics

2 answers

A liquid will boil when its vapor pressure at the given temperature equals the [atmospheric] pressure above the liquid.

I could not find a vapor pressure value of water at 90 degrees, but,
At 86 degrees F, the vapor pressure of water is about 31.8 mmHg.
If you lower the pressure above water to 31.8 mmHg at 90 degrees F, the water will boil.

31.8 mmHg is about .042 atmospheres.

2006-06-18 03:09:36 · answer #1 · answered by mrjeffy321 7 · 1 0

90 F is approx 32 C. At 32 C the vapour pressure of water is 4.7582 kPa. A standard atmosphere is 101.325 kPa. So its 0.047 atmospheres or 35.7 mm of mercury.

2006-06-18 03:23:38 · answer #2 · answered by Epidavros 4 · 0 0

fedest.com, questions and answers