If a positive x a positive = a positive, and a negative x negative = a positive...what is the answer here?
2006-06-17 16:28:07 · 21 answers · asked by Savant 2 in Science & Mathematics ➔ Mathematics
4i
The i stands for imaginary number which is square root of negative one too.This is the square root of negative one times four. Therefore 4i.
2006-06-17 16:31:03 · answer #1 · answered by mr. jones 5 · 1⤊ 0⤋
4
2006-06-17 16:32:04 · answer #2 · answered by leah 1 · 0⤊ 0⤋
There are things called imaginary numbers.
Although you can't really do a root of a negative, you can keep an imaginary 4. Eventually in algebraic manipulation you might be able to take the term to a power giving back a legal negative result.
If you can't cancel your imaginary numbers this way then you, in fact, have an unsolvable problem.
2006-06-17 16:34:48 · answer #3 · answered by Science teacher 3 · 0⤊ 0⤋
-ve numbers have no square roots is not accpeted.
-16 has a square root. It is 4i where i=square root of -1 and is kept as an imagimary number. Ask your MAth teacher, for a more detailed explanation or don't waste 5 pts asking such foolish questions.
2006-06-17 17:02:06 · answer #4 · answered by Patrick Mondal 3 · 0⤊ 0⤋
the square root of -16 is 4i
it breaks down like this
square root -16 = i square root 16
which is i times 4
which is 4i
2006-06-17 16:43:48 · answer #5 · answered by whitetigerlizard 2 · 0⤊ 0⤋
4i is the answer. The imaginary number i is defined as the square root of -1.
2006-06-17 16:31:36 · answer #6 · answered by KiLLa 2 · 0⤊ 0⤋
its not possible to have a square root of a negative number, sooo there's no square root of -16
2006-06-17 19:19:38 · answer #7 · answered by laurennn 3 · 0⤊ 0⤋
There are two results: 4 and -4
2006-06-23 12:44:21 · answer #8 · answered by tdw 4 · 0⤊ 0⤋
Negative numbers can not have square roots.
2006-06-17 16:31:44 · answer #9 · answered by John Luke 5 · 0⤊ 0⤋
+/- 4i, where i is an imaginary number equal to the square root of (-1)
2006-06-18 04:47:32 · answer #10 · answered by jimbob 6 · 0⤊ 0⤋