If an arrow is shot vertically up and 3 s later it is at 35 m in height. How long does it take to come down?

Answer 1

1.Compute initial velocity V0
Using equation S=V0*t-(g*t^2)/2 we find that the initial velocity V0=35/3 + 3g/2
2.What ever goes up must come down V0*t=-(g*t^2)/2 t=2*V0/g
3.Total time travel = 2t
You to the math

Best

Hint: the arrow will stop midair in about 5.3 seconds

Answer 2

1, --- Calculate the initial velocity with which it was shot.
s= 35m
t= 3 sec
g = 10 m/s^2

s= ut -1/2gt^2

35 = u3 -45
u = 80/3 m/s
----->Calculate the time taken to reach highest point
now arrow was therefore shot at 80/3 m /sec
at top point v =0
u = 80/3
g = 10m/s
v = u-gt
t = 8/3 sec

time to fall back is same so 16/3 sec to go up and down =5.33sec round trip .

(Ps Question : )
if the velocity becomes 0 after 8/3 = 2.67sec how come arrow climb 35m after 3 sec as per this simple calculation)

Answer 3

The critical issue in this question concerns the velocity of the arrow when it is at the 35m point. In general, objects shot vertically will take the same amount of time to fall from peak as they took to reach the peak.

They have a certain amount of energy when they are released. Gravity slows them until that initial kinetic force reaches zero, then they begin to fall and gravity accelerates them to the same speed they had when they were shot into the air.

So if the arrow took 3 seconds to reach its peak, it will take 3 seconds to fall back to earth.

Answer 4

Unless that is the peak height acheived by the arrow (in which case it would take 3 seconds to come back down), there is no way to tell. This is excluding all friction and drag acting on the arrow.

Answer 5

first of all I need to Know its velocity and rate of deceleration to know how long and how high it is when it starts to fall. Then given that gravity exerts a force of 32ft/s^2 I can determin the time it takes to reach the earth. This is also dependent on what kind of air friction It will encouter during its fligt. But if you want to know if it is at 35m and assuming there is no air friction how long will it take then this is the answer. 35*3.28=32x +32. Where x is the seconds. so 114.8-32/32=x so x = 2.5875 seconds

Answer 6

3 seconds. Assuming your taking a basic physics class, the arrow follows a parabolic path. Therefore, the time it takes to reach the apex is half the total flight time.

Answer 7

The object is at rest at height of 35m, so its initial velocity u = 0.

ht. = ut + 1/2gt^2
35m = (0 x t ) + (1/2 x 9.8m/s^2 x t^2)
t^2 = 35 / 4.9 = 7.1429 s^2
t = 2.6726 seconds (approx.) (Ans)

Answer 8

If it hits a bird about 3-4 seconds!

Answer 9

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Answer 10

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