2006-06-16 20:06:39 · 11 answers · asked by ninin a 1 in Science & Mathematics ➔ Mathematics
I think you have to know how many degrees the segment is. Then, calculate the area of the entire circle:
PI x radius ^ 2 (squared)
Then, divide the degrees in the segment by 360, so if your segment is 54 degrees, it's:
54/360 = .15
Then, multiply the result of the 2nd calculation (.15 in the example) by the area of the circle you calculated in step 1, and there's your answer.
There's probably a more elegant way, but it's been 25 years since I took a trigonometry or algebra course.
2006-06-16 20:14:29 · answer #1 · answered by Flyboy 6 · 1⤊ 0⤋
Area of circle segment = (22/7)*(r^2)*(A/360).
Here r = radius, A=angle of the segment at its centre of the whole circle.
If the segment is 'D' shaped, then area = (((22/7)*(r^2))-(A^2))/4
Here, r=radius, A=length of the straight edge. Here 'r' should be calculated hypothetically. Here r=((2*A^2)^0.5)/2. This formula is applicable only when the straight line is one of the sides of the maximum sized square that can be fit into the circle.
2006-06-16 21:16:20 · answer #2 · answered by K.J. Jeyabaskaran K 3 · 0⤊ 0⤋
Suppose theta is the angle prescribed at the center of the circle segment and r be the radius of the circle. Then area of the circle segment (or we call as sector) is (theta*r^2)/2.
2006-06-16 20:19:15 · answer #3 · answered by ragu 1 · 0⤊ 0⤋
JOIN THE ENDS OF THE CHORD TO THE CENTRE OF THE CIRCLE. SUBTRACT THE AREA OF THE TRIANGLE SO FORMED FROM THE AREA OF THE SECTOR.
2006-06-16 20:23:55 · answer #4 · answered by Ranjani (India) 2 · 0⤊ 0⤋
pie*r*r gives you area of circle
if you know the length of the arc:
then area of that segment is r*l/2, where l is length of the arc.
if you know the portion of cell it cuts.. say that's 1/5th of circle
then area is pie*r*r/5
2006-06-16 20:14:05 · answer #5 · answered by Varun G 3 · 0⤊ 0⤋
area of a circle is what you are looking for, i assume..
it's pi times the radius squared.
2006-06-16 20:10:29 · answer #6 · answered by smokes_girl 5 · 0⤊ 0⤋
Area Of Segment = r^2 [ pi * theta - sin theta ]
[ ------------ ------------ ]
[ 360 2 ]
r = radius
theta = angle of the arc
2006-06-16 20:23:43 · answer #7 · answered by nayanmange 4 · 0⤊ 0⤋
area of seg. = r*r ( pi*central angle/360 - sin of central angle/2)
2006-06-17 03:12:50 · answer #8 · answered by Aastha 4 · 0⤊ 0⤋
K = r^2[theta - sin(theta)]/2
K = r^2arccos([r - h]/r) - (r - h)sqrt(2rh - h^2)
K = r^2arccos(d/r) - d sqrt(r^2 - d^2)
2006-06-17 03:41:45 · answer #9 · answered by Sherman81 6 · 0⤊ 0⤋
something the above
2006-06-17 02:46:58 · answer #10 · answered by gari 3 · 0⤊ 0⤋