I believe the answer is $566,400
You can find this using the formula
(((200+400+600+800+1000)*6
-200)*2+
(400+800+1200+1600+2000)*6
-400*2)*8;
where we subtract $200 and 2x$400 because we assume the daily doubles are under those squares.
2006-06-16 19:31:17
·
answer #1
·
answered by SNoble 1
·
3⤊
1⤋
There are two rounds of Jeopardy, single and double Jeopardy. In single Jeopardy, the values go from 200-1000 in each category and there is one daily double. Therefore, if the daily double is one of the 200 squares and you answer all of the questions right, and then choose the daily double, bet everything and answer it right you can make:
2+4+5+6+8+1000=3500•6-200= $20800. But you can get the daily double on the $200 square for a total of 20800•2=$41600 for the first round.
Now in the second round, a maximum can occur if both of the daily doubles are $400. Then you can receive 41600+2•3500•6-400-400= 41600+42000-800= 82800. Then you get one of the daily doubles and get 82800•2=165600, then get the other daily double and get 165600•2=331200. Finally, you answer the final Jeopardy (risking all) and get 331200•2=$662,400
Therefore the most money you can win on Jeopardy in a single day (under amazingly special circumstances) is $662,400.
2006-06-17 02:36:42
·
answer #2
·
answered by Eulercrosser 4
·
0⤊
0⤋
1st Round:
3000 per category * 6 Categories=18,000-200 = 17800
(Daily Double under 200)
17800*2 =35600 At the end of the first round
2nd Round:
6000 per category * 6 Categories = 36000-400-400=35200
35600 + 35200 = 70800*4=283,200*2=
566,400
2006-06-17 05:17:41
·
answer #3
·
answered by z_o_r_r_o 6
·
0⤊
0⤋
the answer is between 204,000 Minimum to 213,600 max
2006-06-17 09:07:38
·
answer #4
·
answered by ccctvman 2
·
0⤊
0⤋
I think maybe you should ask Alex Trebek this question.
2006-06-17 02:19:56
·
answer #5
·
answered by goodies100 5
·
0⤊
0⤋
154000
2006-06-17 02:22:22
·
answer #6
·
answered by andrew c 2
·
0⤊
0⤋