Board Reads:
7c 7h 8c 8d 4d
Player 1 has: Jc 5c
Player 2 has: 3c 4c
Who Wins?
2006-06-16 14:46:33 · 17 answers · asked by jugglaman 4 in Games & Recreation ➔ Card Games
Texas Holdem uses the best FIVE cards, so Player 1 wins with the two pair AND the Jack kicker.
2006-06-16 16:35:13 · answer #1 · answered by BenBen1205 2 · 4⤊ 2⤋
Player 1 Wins with two pair 8's and 7's with a jack kicker
The extra set of fours doesn't come into play since it is the best 5 card hand.
2006-06-16 14:50:36 · answer #2 · answered by optionseeker1989 3 · 0⤊ 0⤋
Player 1 with Jack high 2 pair
2006-06-16 14:49:51 · answer #3 · answered by Chuck Dhue 4 · 0⤊ 0⤋
Jc 5c, the jack high wins with the sevens and eights. Player two has a pair with the four on the board, but the pair of fours is lower than the two pairs on the board.
2006-06-16 17:08:58 · answer #4 · answered by kevin w 1 · 0⤊ 0⤋
Player 1 with 2 pair and jack high
2006-06-16 18:00:17 · answer #5 · answered by barron44 2 · 0⤊ 0⤋
Player 1 would win with 2 pair: sevens and eights with jack kicker
2006-06-16 16:52:27 · answer #6 · answered by Anonymous · 0⤊ 0⤋
Even though player one has the winning hand if player two bet a large amount at the end, player one would probably have folded as player one didn`t have a very strong hand and any Ace King Queen Seven or Eight would have beaten him.
But of course it would have taken some balls for player two to make a big bet as he/she didn`t have any hand either.
2006-06-16 15:35:06 · answer #7 · answered by MARTIN B 4 · 0⤊ 0⤋
The best 5 card hand which would be player one with Jack high and the two pair in the Flop, river and turn.
2006-06-17 01:00:23 · answer #8 · answered by mikeae 6 · 0⤊ 0⤋
Player 1, because his hand of the best 5 cards is 7788J. Player 2 only has 77884.
2006-06-16 14:51:27 · answer #9 · answered by Anonymous · 0⤊ 0⤋
player 1 - two pair with a jack kicker
2006-06-16 14:50:20 · answer #10 · answered by UNITool 6 · 0⤊ 0⤋