Math help please!!word problems?

Question

The perimeter of a rectanglular lot is 74 ft. the cost of fencing along the 2 lengths is $1 per foot, and the cost of fencing along the 2 widths is $4.50 per foot. find the dimensions of the lot if the total cost is $159

Answer 1

Let the width be x ft and the length be y ft.
So perimeter is 2x + 2y = 74
or x+y=37........(1)

Calculating cost of lengths....
2y*1 = 2y

Calculating cost of widths....
2x*4.5 = 9x

Total cost = 2y +9x = 159........(2)

Solving (1) and (2) simultaneously you get x(width) = 12.14 ft and y(length) = 24.86 ft

Answer 2

let x be the length and y be the width
so 2x+ 2y = 74 (the total perimeter)

cost along the length = $1 * 2x
cost along the width = $4.5 *2y
total cost = 2x + 9y = 159

solve the 2 equations simultaneously to get
7y = 85 => y = 12.14 feet
2x = 74 - 2(12.14) = 49.71 => x = 24.86

so, the dimensions are 24.86 feet (length) by 12.14 feet (width)

Answer 3

The lot is rectangula, therefore the perimeter is 2*l+2*w=74
on the other hand the cost will be:$159/74 = (2*l/1)+(2*w/4.50)

you have two equations and two unknowns

There you go

Answer 4

2L + 2W = 74
2L + 9W= 159
7W = 85
W = 12 1/7

L = 37 - 12 1/7 = 24 6/7

The width of the lot is 12 1/7 ft (12.14) and the length is 24 6/7 ft (24.86)

Answer 5

In deference to _boaz, I'll just give a "hint" since you are obviously a known student.

Let X = equal length, in feet, of two opposing sides and
let Y = length of other two sides of rectangle, Then

2X($1.00)+2Y($4.50) = $159

You have 2 unknowns X,Y and so you need two equations to solve problem. So you have to form the other equation and then find the solution.

Answer 6

Equations: 2L+2W=74 and 2($1)L+2($4.50)W= $159
Solve 2 equations with 2 unknowns

Answer 7

2x+2y=74

2x+2*4.5y=159
2x+9y=159

7y=159-74=85
y=85/7=12.14

2x+170/7=74
x=37-85/7=24.86

width: 12.14, length: 24.86

Answer 8

15w x 12L x 15w x 12L