recall the specific heat of water
2006-06-16 13:32:46 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
4.184 J/g C° X difference in temp X Mass=
4.184 J/g C° X 8.7 C X 450g = 16,380.36 joules
glad i could help
2006-06-16 13:36:25 · answer #1 · answered by monomat99 3 · 0⤊ 0⤋
Equation for it truly is: Q = mC(delta T) delta skill replace in temperature. Water isnt replacing area so purely the Co-efficent necessary is 4.184 J/g C therefore: Q = fifty 5.6g x 4.184 J/g C x (seventy 8.a million- 40 3.2)C All gadgets cancel out except Joules Q = 8118.8 Joules Q = 8120 Joules through sig. figs.
2016-10-31 00:37:50 · answer #2 · answered by Anonymous · 0⤊ 0⤋
This looks like a homework question but I'll give you a hint.
change in temperature x heat capacity x mass
8.7 1.0 450.0
Check your units but this one is easy.
(of course this formula uses the normal simplification that the heat capacity of water is exactly 1.0 across the temperature range)
2006-06-16 14:34:20 · answer #3 · answered by enginerd 6 · 0⤊ 0⤋
the answer is 8.7*4.2*450=1890*8.7=16443 J
2006-06-16 17:07:00 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Q = mcT
Use it.
2006-06-16 13:34:24 · answer #5 · answered by TheAnomaly 4 · 0⤊ 0⤋