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Some of you people are too mathematically literal than others. Dont you combinitorial fanatics know what a combination lock is,or do you just sit in your room and do math problems? Locks dont care about mathematical combinitorics! They are obviously permutations.
Yea right, 3-20-14 will work on a combination lock that wants 20-3-14!! NOT!!

So what that whoever coined the nomenclature "Combination Lock" was mathematically inaccurate? It is really a permutation lock, and YOU KNOW IT! Or maybe you are so cloistered from human reality that you dont really know. Get a life.

2006-06-16 15:03:24 · answer #1 · answered by Scott R 6 · 0 3

10*5+1

2006-06-16 13:51:18 · answer #2 · answered by A Dizzle 4 · 0 0

10^5

2006-06-17 03:15:49 · answer #3 · answered by gari 3 · 0 0

10^5

2006-06-16 14:23:07 · answer #4 · answered by Anonymous · 0 0

10^5 +1.

2006-06-16 13:25:37 · answer #5 · answered by cyanne2ak 7 · 0 0

nPr = (n!)/((n - k)!)
10P5 = (10!)/((10 - 5)!)
10P5 = (10!)/(5!)
10P5 = (10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1)/(5 * 4 * 3 * 2 * 1)
10P5 = 10 * 9 * 8 * 7 * 6
10P5 = 30240

ANS : 30240 possible combinations

Since 01234 can also be 43210 and still be a different combination, this would be a permutation problem. See site below to see what i mean.

2006-06-16 13:50:54 · answer #6 · answered by Sherman81 6 · 0 0

1) I'm assuming that by "different predictions", you mean "sets of 20 different predictions". For each game, he can make one of two predictions: either one team wins, or the other team wins. So that means there are 2^20 different sets of predictions he could make. 2) There are only 4 different 1-digit numbers you could make. Likewise, there are 4*4 different 2-digit numbers you could make, and so on. So there are 4 + (4*4) + (4*4*4) + (4^4) + (4^5) such numbers. 3) A rotary dial?!? Geez, how old is this textbook?

2016-05-19 21:56:34 · answer #7 · answered by Anonymous · 0 0

Are all dials used to open the lock? If so the answer is 10 to the 5th power

2006-06-16 15:26:47 · answer #8 · answered by rabidtrax 1 · 0 0

You didn't say if each dial is only set to one number. If each dial must be unlocked with a 3 digit combination, then the answer is much greater than 100,000.

2006-06-16 14:26:44 · answer #9 · answered by brooks163 3 · 0 0

_ _ _ _ _ Five empty slots

0 - 9 10 numbers possible in each

10x10x10x10x10 or 10^5

2006-06-16 13:26:52 · answer #10 · answered by darpachief83 2 · 0 0

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