25x^2=13 do i times by 2 then divide by 13..........???solving for x?

Question

2(x-5)^2=3.............25 divide into 2 minus 3.........correct to solve for x

x^2+4x+4=7 do i factor from the left-hand side first............

completing the square of these quadratic equations.....i am so lost....please help me.........

x^2-6x-3=0

2x^2-8x+5=0

Answer 1

you divide both sides by 25, you should have either a fraction or decimal, and then you should have x^2= 13/25, and then take the square root of both sides. you will have x=__.
2(x-5)^2=3.............25 divide into 2 minus 3.........correct to solve for x

x^2+4x+4=7
.. You should get all numbers on one side to where it would be.. x^2+4x-3=0. then factor

completing the square.
x^2-6x-3=0

2x^2-8x+5=0

I never did understand completing the square. If you don't have to show your work on completing the square, then do it a way you do know. That's how I always did it. And then have your teacher sit down and show you.

Answer 2

What? I'm confused by your elipises (......).

25x^2=13 First divide by 25 then take the square root of both sides..

2(x-5)^2=3.............25 divide into 2 minus 3.........correct to solve for x
Divide by 2 then take the square root of both sides. Then add 5 to both sides.

Answer 3

25x^2 is the same thing as 25 * x * x, the ^2 is "to the second power". To solve for x you would then divide 13/ 25, so you would have x*x=13/25. Take the sqrt of 13/25 to find x.
sqrt(x*x)=sqrt(13)/sqrt(25)

x=sqrt(13)/5

Answer 4

No. Divide by 25 and take the square root of that product.

Answer 5

Square root then divide by 5.

Answer 6

25x^2 - 13 = 0

Use quadratic formula to find roots: a = 25; b = 0; c = -13

{+/- sqrt [(-4)(25)(-13)]} / (2*25) = [+/- sqrt (1300)] / 50 = +/-(sqrt 13) / 5 = approximately +/- .7211

Answer 7

25x^2=13 ---divide by 25
x^2=13 ------squaire root
x = +V13 or x = -V13

Answer 8

solve it algebraicly