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2006-06-16 09:26:42 · 4 answers · asked by STANLEY G 1 in Science & Mathematics Mathematics

4 answers

What is the function? I assume it is

(dy/dx is equal to 1 only if y=x+C whre C is a constant)

To prove use the definition of the derivative which is dy/dx as a limit of delta_x appraching of (delta_y/delta_x)
we have
y2-y1=x2+C-x1-C then
delta_y=x2-X1

delta_y/delta_x=(x2-x1)/(x2-x1)=1 QED
(the is no need to take a limit, however in must be used. I hav eommited it for lack of better representation)

Best

2006-06-16 09:29:33 · answer #1 · answered by Edward 7 · 0 0

this is not a theory that we need to prove, the equation which has dy/dx=1 is y=x+a

2006-06-16 16:31:59 · answer #2 · answered by L_n_C_fReAk 1 · 0 0

The derivate of y = x + c is dy/dx=1. (c is any number)
The proof.
y + dy = (x +dx) + c
Since y = x + c you get
x + c + dy = x +dx + c
So dy =dx or dy/dx=1

2006-06-16 17:54:36 · answer #3 · answered by Thermo 6 · 0 0

This is true only when y= x+ constant.

2006-06-16 16:30:04 · answer #4 · answered by Vivek 4 · 0 0

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