not the same set but different 5 number combos out of 55 numbers. please help
2006-06-16 04:57:04 · 7 answers · asked by primet21 3 in Science & Mathematics ➔ Mathematics
there are some very math savy people out there and appreciate the responses from sherman and the other guy who gave me the formula,but i need the formula to be broken down say in elementary form so i can figure it out so please break it down step by step...i have not taken algebra in over 15 years i dont remember too much of equation terminolgy... thanks ....
2006-06-16 06:09:43 · update #1
use this formula
55x54x53x52x51/120
2006-06-16 06:34:45 · answer #1 · answered by pandiin 2 · 7⤊ 1⤋
For combination, the formula is
No. of combination = n C r
where n is the no. of choices
r is the no. of value used for the combination
U also can use this, its the same
No. of combination = (n!)/[(n-r)!(r)!]
where n and r is the same as above and ! is the n value multiply by (n-1),(n-2),(n-3),...,3,2,1
So ur answer is
No. of combination = (55 X 54 X 53 X 52 X 51)/(5X4X3X2X1)
2006-06-16 05:43:25 · answer #2 · answered by sumone^^ 3 · 0⤊ 0⤋
It depends on if the numbers can be repeated. If not then its really simple you can only have one of the numbers in each slot. so you would get 55*54*53*52*51 if it can repeat then 55*55*55*55*55. and there is your answer as long as your not calculating probabilities.
2006-06-16 05:02:58 · answer #3 · answered by Chad N 2 · 0⤊ 0⤋
Use the binomial theorem. THe answer is 55 choose 5, as long as the numbers are all different.
2006-06-16 18:33:23 · answer #4 · answered by Pendejo 2 · 0⤊ 0⤋
5 times 55 (i think)
2006-06-16 05:21:01 · answer #5 · answered by dylan_ediger 1 · 0⤊ 0⤋
combination
55*54*53*52*51
permutation
55^5
2006-06-16 07:24:39 · answer #6 · answered by ana m 1 · 0⤊ 0⤋
nCr = (n!)/(k!(n - k)!)
55C5 = (55!)/(5!(55 - 5)!)
55C5 = (55!)/(120(50)!)
55C5 = 3478761
2006-06-16 05:18:33 · answer #7 · answered by Sherman81 6 · 0⤊ 0⤋