What is the function that describes this problem?

Question

Suppose you throw a baseball straight up at a velocity of 64 feet per second. A function can be created by expressing distance above the ground, s, as a function of time, t. This function is s = -16t2 + v0t + s0
•16 represents 1/2g, the gravitational pull due to gravity (measured in feet per second2).
•v0 is the initial velocity (how hard do you throw the object, measured in feet per second).
•s0 is the initial distance above ground (in feet). If you are standing on the ground, then s0 = 0.

Answer 1

Jennifer, I'm a little bit puzzled about your question because you're asking for what the funtion is and you have it written there. The funtion is s = -16t2 + v0t + s0
What I really think you want is the solution. Correct? Well, here's how you get that. You put in 0 for s0, and 64 for v0. ALSO, s, on the left side of the equation, is also zero because it will land back on the ground when it's done. When you solve using these numbers, the only variable left is t. And when you do the algebra,
0 = -16t2 + 64t + 0

16t2 = 64t

16t = 64

t = 4 seconds, that is.

I hope this works. I'm a physics teacher. If you need further clarification for this problem, or if you need help with any others, feel free to write me at [e-mail]
I'll be glad to help!

Answer 2

Since V0= 64 f/s
Then S = 64 t - 16 t^2 + your length with your hand up in feet