solving math problem.. need help!!!?

4 ⤊

solve for x:

sinx = cscx

pls help me!!
thanks!

2006-06-15 22:02:33 · 3 answers · asked by *hi* 4 in Education & Reference ➔ Homework Help

i think ur question meant sinx = cosecx
sinx = 1/sinx
sin^2x = 1
sinx = 1
sinx is 1 at 90degree
thus x = 90 degree

2006-06-15 22:08:58 · answer #1 · answered by PaRtY AnGeL 3 · 4⤊ 2⤋

sinx=cosecx
sinx=1/six
sin^2x=1
sinx=Â±1.
general solution is nÏÂ±Ï/2

where n is an integer.

2006-06-16 17:09:06 · answer #2 · answered by Gladiator 2 · 0⤊ 0⤋

csc x is simply 1/sin x, thus:
sin x = 1/sin x
sin x=Â±1
x=Â±Ï/2

2006-06-16 05:10:45 · answer #3 · answered by Pascal 7 · 0⤊ 0⤋