1.One guy has Rs. 100/- in hand. He has to buy 100 balls. One football costs Rs. 15/, One Cricket ball costs R

Question

1.One guy has Rs. 100/- in hand. He has to buy 100 balls. One football costs Rs. 15/, One Cricket ball costs Re. 1/- and one table tennis ball costs Rs. 0.25 He spend the whole Rs. 100/- to buy the balls. How many of each balls he bought?

Answer 1

one plausible answer can be: he bought 100 cricket balls which cost rs 100 and he has 100 balls.
You have to give one more condition for this problem to be solved otherwise!

Answer 2

80 tballs 4 foothballs 16 cricket balls Total No. of balls - 100 Cost = 20 + 60 + 16 = 96 start your equation with: .25x + 15y + z = 100 find for x = (100 - 15y -z)/,25 0.25x+x=100 1.25x=100 x=80 you can figure out the rest from here...

Answer 3

x + y = 100
15x + .25y = 100

Multiply top by -.25

-.25x - .25y = -25
15x + .25y = 100

14.75x = 75
x = (75/14.75)
x = (7500/1475)
x = (300/59)
x = about 5

x + y = 100
(300/59) + y = 100
y = 100 - (300/59)
y = (5900 - 300)/59
y = (5600/59)
y = about 95

5 footballs
95 table tennis balls

With $1.25 remaining

Answer 4

there are a number of answers for this question like 100 cricket balls,400 table tennis balls,6 footballs & 8 cricket balls & 8 table tennis balls etc.

Answer 5

After one lame calculation I come to know that the answer will be only 100 Cricket balls,no other type of balls.

Answer 6

let x=no. of fb, y=no. of cb & z=no. of tb
eq. 1 - x+y+z=100
eq.2- 15x+y+0.25z=100

by soiving eq.1 we get
z=100-(x+y)

putting this in eq.2 n by solving it , we get

Foot balls (x)=3
Cricket balls(y)=41
& Tennis Balls(z)=56


total= 100 balls


thank you! guys

Answer 7

x+y+z=100............................(1)
15x+y+0.25z=100.....................(2)
so solving both equation we get x=3z/56 which means x/z=3/56 and using this x=3 and z=56 because neither x nor z can have value greater than 100.
so x/z cant not be 6/112 or 12/224 etc so x=3 and z=56 and y=41
hence solved

Answer 8

there are many possibilities more conditions should be given

Answer 9

how can two equation be solved containing 3 variable............?? the two persons who have solved the math please upload the details of the calculation..........