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t^2-12t+c

i would like you to explein it to me, thanks.

2006-06-15 17:54:51 · 11 answers · asked by NONAME 1 in Science & Mathematics Mathematics

i thin kyou have to use the formula

x=-b/2a

but i dont know exactly how to do it.

2006-06-15 18:00:48 · update #1

11 answers

t^2 - 12t + c
c = 36

Thats if you want to have a perfect square polynomial.

If you would like to tell me a little more, like maybe what one of the factors are, or zeros are, and i can tell you what c is.

2006-06-16 03:45:56 · answer #1 · answered by Sherman81 6 · 4 0

i think this is an integral or differential operation am i right ? this situation there's no way to find the value of c.... because c is unknown value after you do the integral operation to a function... in this case that the function is 2t - 12 when you do the integral function it become t^2 - 12t + c... therefore.. the value of c is likely impossible to be found.... with out any additional information

2006-06-15 18:28:32 · answer #2 · answered by mick-sls 2 · 0 0

You can't find the value of C if the expression isn't equal to something.

EDIT: Even with your new information it doesn't help. X isn't in the equation anywhere, you need either the value of T, C, or equal to something to just simplify. You can email me if you need help and can figure out what the question is asking. I'll be around for a little while.

2006-06-15 17:58:17 · answer #3 · answered by Swarms 3 · 0 0

this is an incomplete equation.
However if t^2-12t+c = 0, then c = 2t(6-t), u should know the value of t

2006-06-15 20:52:37 · answer #4 · answered by payal_kothari_acclaris 2 · 0 0

you cant find a value for c since you have incomplete info
t^2-12t+c is incomplete since it must be an equiation

by your given any value could be possible

if you mean all possible values such that the roots are integers
values for c --------------------------------------------- roots
11 ------- (t-11)(t-1) vice versa ---------- 11 and 1
20 ------- (t-10)(t-2) vice versa ---------- 10 and 2
27 ------- (t-9)(t-3) vice versa ------------- 9 and 3
32 ------- (t-8)(t-4) vice versa ------------- 8 and 4
35 ------- (t-7)(t-5) vice versa -------------- 7 and 5
36 ------- (t-6)(t-6) vice versa ------------- 6

in your new information
x=c
b is the coefficient of the second term whis is -12
a is the coefficient of the first term whis is 1

2006-06-15 18:07:36 · answer #5 · answered by Croasis 3 · 0 0

that is really an "expression" no longer an equation. we do no longer have a fee to remedy with. Did you propose remedy radius of circle? C = pi cases r^2 we haven't any wide-spread to paintings with.

2016-11-14 20:26:57 · answer #6 · answered by ? 4 · 0 0

This isn't an equation, so there is no value of c. Did you type the problem correctly?

2006-06-15 17:58:34 · answer #7 · answered by Anonymous · 0 0

I am very sorry, but you have not provided any information. From what you have, c could literally be anything.

2006-06-15 17:58:12 · answer #8 · answered by powhound 7 · 0 0

this is incomplete. your missing the other side of the eq.

2006-06-15 17:58:17 · answer #9 · answered by absynthian 6 · 0 0

RHS=??

2006-06-15 18:05:45 · answer #10 · answered by ramesh raman 1 · 0 0

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